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3 years ago

JKLM is a rhombus. KM is 6 and JL is 8. Find the perimeter of the rhombus.

Mathematics

2 answers:

yKpoI14uk [10]3 years ago

5 0

The perimeter of rhombus JKLM is 28.

slava [35]3 years ago

3 0

Cut into four triangles. The middle to M will be 3 and the middle to L will be 4. a^2+b^2=c^2... 3^2+4^2=c^2, square root C and get the hypotenuse for one side. Then multiply it by 4 to get the perimeter.

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Answer:

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tekilochka [14]

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Step-by-step explanation:

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Read 2 more answers

Given the system of equations:

mr_godi [17]

Answer:

Step-by-step explanation:

Given the system of equations:

2x + 3y = 15

X + 3y = 0

What is x?

2x + 3y = 15

X + 3y = 0 subtract the bottom equation fron the top one

2x - x + 3y - 3y = 15 - 0 see how the 3y - 3y equates to zero

2x - x = 15

x = 15 Now for extra credit what is y?

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15 + 3y = 0

15 - 15 + 3y = 0 - 15

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-5

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