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lana [24]
3 years ago
5

Pythagorean Theorem in Three Dimensions

Mathematics
2 answers:
exis [7]3 years ago
4 0

Answer:

A is

✔ an edge

.

B is

✔ a vertex

.

C is

✔ a face

.

Step-by-step explanation:

gregori [183]3 years ago
3 0

Answer:

Step-by-step explanation:

I think 3 5 6

You might be interested in
**Spam answers will not be tolerated**
Morgarella [4.7K]

Answer:

f'(x)=-\frac{2}{x^\frac{3}{2}}

Step-by-step explanation:

So we have the function:

f(x)=\frac{4}{\sqrt x}

And we want to find the derivative using the limit process.

The definition of a derivative as a limit is:

\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}

Therefore, our derivative would be:

\lim_{h \to 0}\frac{\frac{4}{\sqrt{x+h}}-\frac{4}{\sqrt x}}{h}

First of all, let's factor out a 4 from the numerator and place it in front of our limit:

=\lim_{h \to 0}\frac{4(\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x})}{h}

Place the 4 in front:

=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}

Now, let's multiply everything by (√(x+h)(√(x))) to get rid of the fractions in the denominator. Therefore:

=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}(\frac{\sqrt{x+h}\sqrt x}{\sqrt{x+h}\sqrt x})

Distribute:

=4\lim_{h \to 0}\frac{({\sqrt{x+h}\sqrt x})\frac{1}{\sqrt{x+h}}-(\sqrt{x+h}\sqrt x)\frac{1}{\sqrt x}}{h({\sqrt{x+h}\sqrt x})}

Simplify: For the first term on the left, the √(x+h) cancels. For the term on the right, the (√(x)) cancel. Thus:

=4 \lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }

Now, multiply both sides by the conjugate of the numerator. In other words, multiply by (√x + √(x+h)). Thus:

= 4\lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }(\frac{\sqrt x +\sqrt{x+h})}{\sqrt x +\sqrt{x+h})}

The numerator will use the difference of two squares. Thus:

=4 \lim_{h \to 0} \frac{x-(x+h)}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}

Simplify the numerator:

=4 \lim_{h \to 0} \frac{x-x-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}\\=4 \lim_{h \to 0} \frac{-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}

Both the numerator and denominator have a h. Cancel them:

=4 \lim_{h \to 0} \frac{-1}{(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}

Now, substitute 0 for h. So:

=4 ( \frac{-1}{(\sqrt{x+0}\sqrt x)(\sqrt x+\sqrt{x+0})})

Simplify:

=4( \frac{-1}{(\sqrt{x}\sqrt x)(\sqrt x+\sqrt{x})})

(√x)(√x) is just x. (√x)+(√x) is just 2(√x). Therefore:

=4( \frac{-1}{(x)(2\sqrt{x})})

Multiply across:

= \frac{-4}{(2x\sqrt{x})}

Reduce. Change √x to x^(1/2). So:

=-\frac{2}{x(x^{\frac{1}{2}})}

Add the exponents:

=-\frac{2}{x^\frac{3}{2}}

And we're done!

f(x)=\frac{4}{\sqrt x}\\f'(x)=-\frac{2}{x^\frac{3}{2}}

5 0
3 years ago
When lines intersect in one place, what are they called?
Deffense [45]
Independent
..............
7 0
3 years ago
Read 2 more answers
Allison can jog 3 blocks in the same amount of time it takes her brother, Blake, to jog 2 blocks. If they keep jogging at the sa
Nitella [24]

Answer:

Blake will jog 12 blocks

Step-by-step explanation:

Allison : Blake = 3 : 2

If they keep jogging at the same rate, how many blocks will Blake jog if Allison jogs 18 blocks?

Allison : Blake = 18 : x

Equate the ratios

3 : 2 = 18 : x

3/2 = 18/x

Cross multiply

3 * x = 2 * 18

3x = 36

Divide both sides by 3

x = 36 / 3

= 12

x = 12

Blake will jog 12 blocks

6 0
3 years ago
Read 2 more answers
8. What are the advantages of switching a quadratic function from standard form into vertex form?
Airida [17]

Answer:

vertex form automatically gives you your vertex and your y intercept so all you need to do is graph. Hope this helps

Step-by-step explanation:

3 0
4 years ago
PLEASE PLEASE PLEASE The graph of g(x), shown below, resembles the graph of f(x) = x^4-x^2 but it has been changed somewhat. Whi
galina1969 [7]
<h2>Answer: D</h2>

Step-by-step explanation:

5 0
3 years ago
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