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mart [117]
3 years ago
11

HELP ME!!!

Mathematics
1 answer:
andrew11 [14]3 years ago
6 0

Answer:

210 is the only choice I see listed that works.

Step-by-step explanation:

I don't know if you know this but you can apply a co-function identity here giving you the equation:

cos(x)=-\frac{\sqrt{3}}{2}.

If you are unsure of the identity sin(90-x)=cos(x) then I can show you another identity that leads to this one.

The difference identity for sine is sin(a-b)=sin(a)cos(b)-sin(b)cos(a).

Applying this to sin(90-x) gives you sin(90)cos(x)-sin(x)cos(90).

Let's simplify that using that sin(90)=1 while cos(90)=0:

sin(90-x)=sin(90)cos(x)-sin(x)cos(90)

sin(90-x)=1cos(x)-sin(x)(0)

sin(90-x)=cos(x)

You can also prove this identity using a right triangle like the one in this picture:  

That missing angle is 90-x since we need the angles in this triangle to add up to 180 which it does:

(x)+(90)+(90-x)

x+90+90-x

x-x+90+90

0+180

180

Anyways you should see that sin(90-x)=b/c while cos(x)=b/c.

Since they are equal to the same ratio, then you can say sin(90-x)=cos(x).

There are other co-function identities you can get from using this idea.

Anyways back to the problem.

We are solving:

cos(x)=-\frac{\sqrt{3}}{2}.

It looks like you have a drop-down menu with answers ranging from 0 to 360.

So I'm going to answer in degrees using the unit circle.

cosine value refers to the x-coordinate.

We are looking for when the x-coordinate is -\frac{\sqrt{3}}{2} which is at \theta=150^\circ , 210^\circ.

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Answer:

Option A

Step-by-step explanation:

Here is how to approach the problem:

We see that all our restrictions for all four answer choices are relatively the same with a couple of changes here and there.
One way to eliminate choices would be to look at which restrictions don't match the graph.

At x<-5, there is a linear function that does have a -2 slope and will intersect the x axis at -7. The line ends with an open circle, so any answer choice with a linear restriction of x less than or equal to -5 is wrong. This cancels out choices C and D.

Now we have two choices left.

For the quadratic in the middle, the vertex is at (-2,6) and the vertex is a maximum, meaning our graph needs to have a negative sign in front of the highest degree term. In our case, none of our quadratics left are in standard form, and instead are in vertex form.

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3 0
2 years ago
Four people recorded the miles they drove and the time they spent driving. The table below shows
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Answer:

C: Charles

Step-by-step explanation:

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8 0
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<u>Understanding:</u>

The sum of a geometric series is, a+ar+ar^2+ar^3+..., with a being the start point and r is the common ratio. We can also use the following formula to make life easier S_n=a\frac{1-r^n}{1-r}, a is your start point, r is the common ratio, and n is the number of terms, which in our case is S7.

<u>Solution:</u>

Our start point is 1, a=1,

The common ratio is 5, r=5,

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Answer:

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Step-by-step explanation:

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