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aliina [53]
2 years ago
9

600(2)/94(0.6(2)+169

Mathematics
2 answers:
kogti [31]2 years ago
5 0

Answer:

2172.7

Step-by-step explanation:

KATRIN_1 [288]2 years ago
4 0

Answer:

the full answer would be 2172.76595745

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Help me please!!!!! Thank you
HACTEHA [7]

Answer:

15/2 in³

Step-by-step explanation:

The formula for the vol. of a pyramid

is

V = (1/3)(area of base)(height of pyramid)

Here, the volume is:

V = (1/3)( [1/2][5 in][9 in] )·(10 in)

   = (9/3)(5/2)(10) in³

    =  450/6 in³   =   150/2 in³  =  75 in³     Volume of the pyramid

5 0
3 years ago
Read 2 more answers
What is the solution
antoniya [11.8K]

Answer:

3,2 or 1

Step-by-step explanation:

5 0
3 years ago
FOLLOW DIRECTIONS PLEASE! WILL MARK BRAINLIEST! MORE QUESTIONS TO COME!
Rom4ik [11]

A) part of it is decreasing, part of it is increasing.  

Going left-to-right, the downhill/negative slope is the decreasing portion (x<-1) and the uphill/positive slope is the increasing portion (x>-1).  

B) The x-intercepts are the points where the graph intersects the x-axis: (2,0) and (-4,0).

C: The y-intercept is the point where the graph intersects the y-axis: (0,-2).

D: There is no absolute maximum.  The graph keeps going up forever.

E: The absolute minimum <u>point</u> is at that bottom, at (-1, -3).  The absolute minimum <u>value</u> is -3, since that's the lowest y-value used.

7 0
2 years ago
Look at the graph .which is the relationship between x and y PLSSS HURRY (100 POINTS
skelet666 [1.2K]

Answer:

it is B

Step-by-step explanation:

6 0
3 years ago
Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

5 0
4 years ago
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