Hello:<span>
the equation is : y = ax+b
the slope is a : a×(4/3) = -1......(
perpendicular to a line with a slope of 4/3) because : 4x-3y =8...y=(4/3)x-8/3 ) </span>
<span>
a = -3/4
y=(-3/4)x+b
the line that passes through (3, -2) :- 2 =
(-3/4)(3)+b
b =1/4
<span> the equation is : y = (-3/4)x+1/4</span></span>
It is an acute triangle because none of its angles are equal to (right) or above (obtuse) 90 degrees.
Answer:

Step-by-step explanation:
![\sf x(4+5) = 54\\\\Applying \ distributive \ property\\\\(x*4) + (x*5) = 54\\\\Distributive\ Property\ is:\\\\A(B+C) = (A*B)+(A*C)\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20x%284%2B5%29%20%3D%2054%5C%5C%5C%5CApplying%20%5C%20distributive%20%5C%20property%5C%5C%5C%5C%28x%2A4%29%20%2B%20%28x%2A5%29%20%3D%2054%5C%5C%5C%5CDistributive%5C%20Property%5C%20is%3A%5C%5C%5C%5CA%28B%2BC%29%20%3D%20%28A%2AB%29%2B%28A%2AC%29%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>