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katrin [286]
3 years ago
13

Find the measure of the arc or central angle indicated. Assume that lines which appear to be

Mathematics
1 answer:
lianna [129]3 years ago
3 0

Answer:

25)

arcQR=60°

26)

arcUWY=240°

27)

arcSU=112°

28)

arcSR=310°

hope it helps

<h3>stay safe healthy and happy.</h3>
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Log 300 =<br> log 3.26 =<br> log 10,000 =<br> log 20 =
ehidna [41]

Answer:

Log300=2.4771

Log3.26=0.5132

Log10000=4

Log20=1.3010

Step-by-step explanation:

log300=2.4771

Log3.26=0.5132

Log10000=4

Log20=1.3010

4 0
3 years ago
A colony of 85 bacteria doubles in size every 126 minutes. What will the population be 378
SVETLANKA909090 [29]

Answer:

680 Bacteria

Step-by-step explanation:

378 is evenly divisible by 126, which is equal to 3.

The first 126 minutes, the 85 bacteria will double to 170 bacteria.

The second 126 minutes (252 minutes total), the 170 bacteria will double to 340 bacteria.

The final 126 minutes (378 minutes total), the 340 bacteria will double to 680 bacteria total.

If this helped, a brainliest would be greatly appreciated!

6 0
3 years ago
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What is the slope of у= 3х — 9​
astra-53 [7]

Answer:

3?

Step-by-step explanation:

3 is the slope intercept I believe

8 0
3 years ago
In a study of wait times at an amusement park, the most popular roller coaster has a mean wait time of 17.4 minutes with a stand
Ann [662]

Answer: A: 0.0031

Step-by-step explanation:

Given : In a study of wait times at an amusement park, the most popular roller coaster has a mean wait time of 17.4 minutes with a standard deviation of 5.2 minutes.

i.e. \mu=17.4 and \sigma=5.2

We assume that the wait times are normally distributed.

samples size : n= 30

Let x denotes the sample mean wait time.

Then, the probability that the mean wait time is greater than 20 minutes will be :

P(x>20)=1-P(x\leq20)\\\\=1-P(\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}\leq\dfrac{20-17.4}{\dfrac{5.2}{\sqrt{30}}})\\\\=1-P(z\leq2.74)\ \ [\because\ z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=1-0.9969\ \ [\text{ By z table}]\\\\=0.0031

Hence, the probability that the mean wait time is greater than 20 minutes.= 0.0031

Thus , the correct answer is A: 0.0031 .

5 0
3 years ago
Russell has a collection of 1,200 pennies. Of these pennies, 25% are dated before 1980, 35% are dated from 1980 to 2000, and the
mars1129 [50]

Answer:

480 pennies dated after 2000.

Step-by-step explanation:

1. Pennies dated before 1980 (x) - 25%,

All pennies (1,200) - 100%.

Then

\dfrac{x}{1,200}=\dfrac{25}{100},\\ \\100x=25\cdot 1,200,\\ \\x=25\cdot 12=300.

2. Pennies dated from 1980 to 2000 (y) - 35%,

All pennies (1,200) - 100%.

Then

\dfrac{y}{1,200}=\dfrac{35}{100},\\ \\100y=35\cdot 1,200,\\ \\y=35\cdot 12=420.

3. Rest pennies are dated after 2000, then

1,200-300-420=480.

5 0
3 years ago
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