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erastovalidia [21]
3 years ago
15

Can I factor this polynomial? 9pr^2+73pr+70r

Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0
R(9p^2+73p+70)
r(9p+10)(p+7)
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You borrow $3750 to buy new fitness equipment.The simple interest rate is 2%. You pay the loan off after 4 years. What is the to
Alinara [238K]
Provided the 2% interest rate. The interest itself over a period of 4 years, compounds to $300. Thus, the total interest plus the cost of the fitness equipment would be a total of, $4,050.
6 0
3 years ago
The product of two numbers is 342. If one number is 18, what is the other nnumber without the use of a calculator show all your
dalvyx [7]
342/18 18 x 10= 180 342 - 180= 162 18 x 9= 90 + 72= 162 10+9= 19 The answer is 19
7 0
2 years ago
I have 3 children. Their ages add up to 21, and when multiplied they equal 75. How old are they?
olganol [36]
So represent the ages as x y and z with each being numbers

x+y+z=21
x times y times z=75
this is really tough for elementary school

one way is to find the factors of 75 or the numbers that add up to 75 and trial and error
use whole numbers becuase this is the world of math so


75=1 times 3 times 5 times 5
possible ages are
3,5,5
1,5,15
1,3,25
add them up

3+5+5=13
1+5+15=21 check
1+3+25=29


their ages are 1, 5 and 15
6 0
3 years ago
Read 2 more answers
A bag contain 3 black balls and 2 white balls.
Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\

b)

Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}

c)

Probability of at least one black( means BB or BW or WB)

 =\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}

d)

Probability of at most one black ( means WW or WB or BW)

=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}

2)

a) Probability both black without replacement

  =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

b) Probability  of one black and one white

 =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

c) Probability of at least one black ( BB or BW or WB)

 =\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}

d) Probability of at most one black ( BW or WW or WB)

 =\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}

6 0
3 years ago
How are area and volume similar? both are 2-dimensional both take up an amount of space both are 3-dimensional both have length,
VARVARA [1.3K]

Answer:

128

Step-by-step explanation:

The area of the larger rectangle is \begin{align*}8(16)=128 \ \mathrm{units}^2\end{align*} and the area of the smaller rectangle is \begin{align*}5(10)=50 \ \mathrm{units}^2.\end{align*} If we compare the areas in a ratio, it is \begin{align*}50:128 \ = \ 25:64 \ = \ 5^2:8^2.\end{align*}

~Vee

6 0
2 years ago
Read 2 more answers
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