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evablogger [386]
3 years ago
14

X⁴+1/x⁴=47,find the value of x³+1/x³​

Mathematics
1 answer:
SOVA2 [1]3 years ago
4 0

Answer:

The value of x^3 + 1/x^3 is 47/x + 1/x^3 - 1/x^5

Step-by-step explanation:

x^4 + 1/x^4 = 47

x^4 = 47 - 1/x^4

x^3 + 1/x^3 = 1/x(x^4 + 1/x^2)

x^4 = 47 - 1/x^4

x^3 + 1/x^3 = 1/x(47 - 1/x^4 + 1/x^2) = 47/x - 1/x^5 + 1/x^3 = 47/x + 1/x^3 - 1/x^5

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TWO points A and B on a plan represent two localities 12 m apart. Given that the segment AB is 6 cm long, find the scale used to
dezoksy [38]

Answer:

The scale used to draw the plan is 1: 200.

Step-by-step explanation:

Given that two points A and B on a plan represent two localities 12 m apart, to determine, given that the segment AB is 6 cm long, the scale used to draw the plan, the following calculation must be performed:

12 m = 12 cm x 100 = 1200 cm

1200/6 = 200

Therefore, the scale used to draw the plan is 1: 200.

5 0
3 years ago
Pleaseeeee someone help due at 10 pm today!<br> 2x^2-x+1=0
hammer [34]

Answer:

No real solutions!!! That is the answer.

Step-by-step explanation:

4 0
4 years ago
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19/100 x g/10 help please :0
Rudik [331]

19g/1000 would be the right answer when simplified.

4 0
3 years ago
Tell whether each scale reduces enlarges or preserves the size of an actual object
mr_godi [17]

Given:

1 m : 25 cm

8 in : 1 ft

12 in : 1 ft

 

First, we convert each variable given on the right:

 

1 m : 0.25 m (this means that 1 meter is made to represent 25 cm)

8 in : 12 feet (this means that 8 in is made to represent 1 feet)

12 in : 12 in (this means that 12 in is made to represent 1 feet)

 

<span>After converting the variables, we can now know if the ratios are enlargement, reduction or preservation. Therefore:

1 m : 25 cm = Enlarge</span>

<span>8 in : 12 feet = Reduce
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4 0
3 years ago
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(x-1)(x-3)(x+5)(x+7)=297
mihalych1998 [28]

First simplify the expression into polynomial form,

(x-1)(x-3)(x+5)(x+7)=297

x^4+8x^3-10x^2-104x+105=297

x^4+8x^3-10x^2-104x-192=0

Now factor into,

(x-4)(x+8)(x^2+4x+6)=0

Which means the solutions are,

x-4=0\implies\boxed{x_1=4}

x+8=0\implies\boxed{x_2=-8}

and then two complex solutions because determinant of the third factor D\lt0,

x^2+4x+6=0

x^2+4x+4=-2

(x+2)^2=-2\implies\boxed{x_3=i\sqrt{2}-2},\boxed{x_4=-i\sqrt{2}-2}

Hope this helps :)

5 0
3 years ago
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