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3 years ago

Slope of (4,6) and (-1,2)

2 answers:

7 0

$\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{We have}\\\\(4,\ 6)\to x_1=4,\ y_1=6\\(-1,\ 2)\to x_2=-1,\ y_2=2\\\\\text{substitute}\\\\m=\dfrac{2-6}{-1-4}=\dfrac{-4}{-5}=\dfrac{4}{5}=0.8$

Sergeeva-Olga [200]3 years ago

4 0

We can use the slope formula to find the slope between these two points:

$\frac{y.2 - y.1}{x.2 - x.1} = m$

2 - 6 / -1 - 4

-4 / -5

Because there are two negatives, they cancel out.

The slope of the line between these two points is 4/5.

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The work of a student to solve the equation 4(2x − 4) = 8 + 2x + 8 is shown below:

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Step 2...first error...when distributing through the parenthesis, u multiply, not add.

4(2x - 4) = 8 + 2x + 8 =
8x - 16 = 16 + 2x <== correction

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3 years ago

In a right triangle sin A=

kherson [118]

Answer:

$sinA=\frac{opposite}{hypotenuse}$

Step-by-step explanation:

Soh-cah-toa is a great way to remember:

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You just remember the first letters : sine= opposite/hypotenuse , for example.

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4 years ago

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Express 35.4% as a decimal

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Answer:

0.354

Step-by-step explanation:

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3 years ago

A random variable X with a probability density function () = {^-x > 0

Sliva [168]

The solutions to the questions are

The probability that X is between 2 and 4 is 0.314
The probability that X exceeds 3 is 0.199
The expected value of X is 2
The variance of X is 2

<h3>Find the probability that X is between 2 and 4</h3>

The probability density function is given as:

f(x)= xe^ -x for x>0

The probability is represented as:

$P(x) = \int\limits^a_b {f(x) \, dx$

So, we have:

$P(2 < x < 4) = \int\limits^4_2 {xe^{-x} \, dx$

Using an integral calculator, we have:

$P(2 < x < 4) =-(x + 1)e^{-x} |\limits^4_2$

Expand the expression

$P(2 < x < 4) =-(4 + 1)e^{-4} +(2 + 1)e^{-2}$

Evaluate the expressions

P(2 < x < 4) =-0.092 +0.406

Evaluate the sum

P(2 < x < 4) = 0.314

Hence, the probability that X is between 2 and 4 is 0.314

<h3>Find the probability that the value of X exceeds 3</h3>

This is represented as:

$P(x > 3) = \int\limits^{\infty}_3 {xe^{-x} \, dx$

Using an integral calculator, we have:

$P(x > 3) =-(x + 1)e^{-x} |\limits^{\infty}_3$

Expand the expression

$P(x > 3) =-(\infty + 1)e^{-\infty}+(3+ 1)e^{-3}$

Evaluate the expressions

P(x > 3) =0 + 0.199

Evaluate the sum

P(x > 3) = 0.199

Hence, the probability that X exceeds 3 is 0.199

<h3>Find the expected value of X</h3>

This is calculated as:

$E(x) = \int\limits^a_b {x * f(x) \, dx$

So, we have:

$E(x) = \int\limits^{\infty}_0 {x * xe^{-x} \, dx$

This gives

$E(x) = \int\limits^{\infty}_0 {x^2e^{-x} \, dx$

Using an integral calculator, we have:

$E(x) = -(x^2+2x+2)e^{-x}|\limits^{\infty}_0$

Expand the expression

$E(x) = -(\infty^2+2(\infty)+2)e^{-\infty} +(0^2+2(0)+2)e^{0}$

Evaluate the expressions

E(x) = 0 + 2

Evaluate

E(x) = 2

Hence, the expected value of X is 2

<h3>Find the Variance of X</h3>

This is calculated as:

V(x) = E(x^2) - (E(x))^2

Where:

$E(x^2) = \int\limits^{\infty}_0 {x^2 * xe^{-x} \, dx$

This gives

$E(x^2) = \int\limits^{\infty}_0 {x^3e^{-x} \, dx$

Using an integral calculator, we have:

$E(x^2) = -(x^3+3x^2 +6x+6)e^{-x}|\limits^{\infty}_0$

Expand the expression

$E(x^2) = -((\infty)^3+3(\infty)^2 +6(\infty)+6)e^{-\infty} +((0)^3+3(0)^2 +6(0)+6)e^{0}$

Evaluate the expressions

E(x^2) = -0 + 6

This gives

E(x^2) = 6

Recall that:

V(x) = E(x^2) - (E(x))^2

So, we have:

V(x) = 6 - 2^2

Evaluate

V(x) = 2

Hence, the variance of X is 2

Read more about probability density function at:

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<u>Complete question</u>

A random variable X with a probability density function f(x)= xe^ -x for x>0\\ 0& else

a. Find the probability that X is between 2 and 4

b. Find the probability that the value of X exceeds 3

c. Find the expected value of X

d. Find the Variance of X

7 0

2 years ago

One bucket of gravel has a mass of 7.05 KG. What is the mass of 20 buckets of gravel in kilograms?

schepotkina [342]

Answer:

D: 141 KG

Step-by-step explanation:

7.05 x 20 = 141

Just multiply the mass of the object by however many objects there are if they all weigh the same.

3 0

3 years ago