What are the zeros of the polynomial function f(x) = x3 – 4x2 – 12x
2 answers:
X³ - 4x² - 12x
x(x² - 4x - 12)
x(x - 6)(x + 2)
x = 0
x = 6
x = -2
The zeros are 0, 6, and -2
<span><span>fx</span>=<span><span><span>x3</span>−<span>4<span>x2</span></span></span>−<span>12x</span></span></span>.<span><span><span><span><span>fx/</span>x</span></span></span>=<span><span><span><span><span><span>x3</span>−<span>4<span>x2</span></span></span>−<span>12x/</span></span>x</span></span>
</span></span><span>f=<span><span><span>x2</span>−<span>4x</span></span>−<span>12</span></span></span>
You might be interested in
Answer:
hope the above solution will help you
Answer:
broken heart thats the last one lol
Step-by-step explanation:
Answer:
ithe answer to your question is going to be c
You should get the app "photomath" that will help out alot!!!
It depends on which variable is eliminated.
If you multiply the second equation by -1 and eliminate the y:
3x - y = 7
-6x + y = -10
-3x = -3 or x = 1
If you multiply the first equation by -2 and eliminate the x:
-6x + 2y = -14
6x - y = 10
y = -4
