What are the zeros of the polynomial function f(x) = x3 – 4x2 – 12x

2 answers:

8 0

X³ - 4x² - 12x
x(x² - 4x - 12)
x(x - 6)(x + 2)
x = 0
x = 6
x = -2
The zeros are 0, 6, and -2

4 0

fx=x3−4x2−12x.‌fx/x‌=‌x3−4x2−12x/x‌

f=x2−4x−12

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