Answer:
Cd2+ : 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d10 or [Kr] 4d¹⁰
Explanation:
Before proceeding to write out the electron configuration of Cd2+, we have to obtain the electron configuration of Cadmium (Cd),
Cadmium has an atomic number of 48, this means that a neutral cadmium atom will have a total of 48 electrons surrounding its nucleus.
The electronic configuration of Cadmium is;
Cd: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10
The shorthand notation is given as;
Cd: [Kr] 4d¹⁰5s²
Cd2+ means that it has two less electrons, hence it's electron configuration is given as;
Cd2+ : 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d10 or [Kr] 4d¹⁰
Answer:
The combustion reaction is the last one, with the C4H12 compound.
Remember that all the combustion reactions has the oxygen as a substract and for products, you'll have CO2 and water.
Explanation:
<span>1.43g x (1 mole / 233g) x (6.022x10^23 particles / mole) = 3.70 x 10^ 21 particles</span>
The poly atomic ion formula for ammonium would be NH4+
Explanation:
answer is permanent dipole dipole forces hydrogen bonding and van see waals forces
