Answer: d
Explanation:
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Answer:
AgNO3
Explanation:
Silver nitrate (AgNO3) is an inorganic compound. Organic compounds usually have 1+ C.
Answer:
P₂ = 2.7 atm
Explanation:
Given data:
Initial temperature = 30°C
Initial pressure = 3.00 atm
Final temperature = -5°C
Final pressure = ?
Solution:
Initial temperature = 30°C = 30 + 273 = 303 K
Final temperature = -5°C = -5 + 273 = 268 K
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
3.0 atm / 303 K = P₂/268 K
P₂ = 3.0 atm × 268 K / 303 K
P₂ = 804 atm. K /293 K
P₂ = 2.7 atm
Well, trees are over 20 feet tall and have trunks that are like in 2 inches and 4.5 feet about the ground. Bushes are smaller than the trees and usually have smaller, woody, bark leafs.
Well im gonna say it would be the same,but not in size.
Hope this helps
<u>Answer:</u> The value of
for the reaction at 550.3 K is 247.83
<u>Explanation:</u>
Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as ![K_{c}](https://tex.z-dn.net/?f=K_%7Bc%7D)
For a general chemical reaction:
![aA+bB\rightarrow cC+dD](https://tex.z-dn.net/?f=aA%2BbB%5Crightarrow%20cC%2BdD)
The expression for
is written as:
![K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
The chemical equation for the production of methanol follows:
![CO+2H_2\rightleftharpoons CH_3OH](https://tex.z-dn.net/?f=CO%2B2H_2%5Crightleftharpoons%20CH_3OH)
The expression of
for above equation follows:
![K_c=\frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)
We are given:
![[CH_3OH]=0.0401mol/L](https://tex.z-dn.net/?f=%5BCH_3OH%5D%3D0.0401mol%2FL)
![[CO]=0.02722mol/L](https://tex.z-dn.net/?f=%5BCO%5D%3D0.02722mol%2FL)
![[H_2]=0.07710mol/L](https://tex.z-dn.net/?f=%5BH_2%5D%3D0.07710mol%2FL)
Putting values in above equation, we get:
![K_c=\frac{0.0401}{0.02722\times (0.07710)^2}\\\\K_c=247.83](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B0.0401%7D%7B0.02722%5Ctimes%20%280.07710%29%5E2%7D%5C%5C%5C%5CK_c%3D247.83)
Hence, the value of
for the reaction at 550.3 K is 247.83