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1 year ago

PLZ HELP?! 50 points Write the correct IUPAC name for the following compound

Chemistry

1 answer:

slamgirl [31]1 year ago

3 0

Answer:

2-ethly-3-5 dimethylheptam

Explanation:

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What is the molality of a solution containing 100 grams of glucose (C6H12O6, molar mass = 180 g/mol) dissolved in 2.5 kg of wate

meriva

Answer:

The answer to your question is molality = 0.22

Explanation:

Data

molality = ?

mass of glucose = 100 g

molar mass of glucose = 180 g

mass of water = 2.5 kg

Process

1.- Calculate the moles of glucose using proportions

180 g ------------------ 1 mol

100 g ------------------ x

x = (100 x 1) / 180

x = 100 / 180

x = 0.56 moles

2.- Calculate the molality

Formula

molality = moles / mass of solvent

- Substitution

molality = 0.56 / 2.5

- Simplification

molality = 0.22

6 0

3 years ago

Chemistry, need answer ASAP!! 50 points and i'll mark brainliest if correct! ^w^

pishuonlain [190]

Answer:

615 g

Explanation:

In order to convert from moles of any given substance into grams, we have to use said substance's molar mass, as follows:

# moles * Molar mass = grams of substance.

Thus, we now calculate the molar mass of beryllium iodide, BeI₂, using the molar masses of the elements:

Molar Mass of BeI₂ = Molar Mass of Be + (Molar Mass of I)*2 = 262.821 g/mol

Finally we calculate how many grams are there in 2.34 moles of BeI₂:

2.34 mol * 262.821 g/mol = 615 g

4 0

2 years ago

A compressed gas cylinder is filled with 5270 g of argon gas. The pressure inside the cylinder is 2050 psi at a temperature of 1

LuckyWell [14K]

Answer:

A compressed gas cylinder is filled with 5270 g of argon gas.

The pressure inside the cylinder is 2050 psi at a temperature of 18C.

The valve to the cylinder is opened and gas escapes until the pressure inside the cylinder is 650. psi and the temperature are 26 C.

How many grams of argon remains in the cylinder?

Explanation:

First, calculate the volume of argon gas that is present in the gas cylinder by using the ideal gas equation:

Mass of Ar gas is --- 5270g.

The number of moles of Ar gas:

$Number of moles of Ar gas=\frac{given mass of Ar}{its atomic mass} \\ =\frac{5270g}{39.948g/mol} \\ =131.9mol$

Temperature T=(18+273)K=291K

Pressure P=2050psi

$2050* 0.0680atm\\\\=139.4atm\\$

Volume V=?

$PV=nRT\\139.4atm * V=131.9mol *0.0821L.atm.mol-1.K-1 * 291K\\=>V=\frac{131.9mol *0.0821L.atm.mol-1.K-1 * 291K}{139.4atm} \\=>V=22.6L$

Using this volume V=22.6L

Pressure=650psi=44.2atm

Temperature T= (26+273)K=299K

calculate number of moles "n" value:

$PV=nRT\\=>n=\frac{PV}{RT} \\=>n=\frac{44.2atm*22.6L}{0.0821L.atm.mol^-1K^-1* 299K} \\=>n=40.7mol$

Mass of 40.7mol of Ar gas:

$mass of Ar gas=number of moles * its atomic mass\\\\ =40.7mol* 39.948g/mol\\\\ =1625.8g$

Answer:

The mass of Ar gas becomes 1625.8g.

8 0

2 years ago

If you are given 1.709 moles of solute, and you dilute it to make 2.10 liters of solution, what is the resulting molarity (M)? (

azamat

Moles/MxL

1.709moles/2.10L =0.814M

4 0

3 years ago

How many grams are 5.83 moles of C2H2

wlad13 [49]

Imagine liking anime

7 0

2 years ago