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xz_007 [3.2K]
4 years ago
15

19. Mr. Johnson owns a restaurant. On Monday morning, his restaurant has 80 steaks in the walk-in cooler. Each day 7 customers o

rder a steak dinner. How many steaks does Mr. Johnson's restaurant have when the restaurant opens on Friday and on Saturday? A. Friday 45, Saturday 38 B. Friday 59, Saturday 52 C. Friday 52, Saturday 45 D. Friday 38, Saturday 31
Mathematics
2 answers:
mixer [17]4 years ago
3 0

The answer is C because you start out with 80 steaks and as you go through the days, subtract 7 each time.


Lera25 [3.4K]4 years ago
3 0

Answer:

C. Friday 52, Saturday 45

Step-by-step explanation:

Mr. Johnson owns a restaurant. On Monday morning, his restaurant has 80 steaks in the walk-in cooler.

Each day 7 customers order a steak dinner.

So, from Monday to Thursday, that is 4 days ; 7\times4=28 steaks were used.

So, when the restaurant opened on Friday, it had 80-28=52 steaks.

And 7 were used on Friday also so remaining were = 52-7=45

Hence, on Saturday there were 45 steaks.

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<u><em>the answer is 225cm3</em></u>

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Andrew McCutchen hit 18 homeruns in 9 baseball games. At this rate, how many homeruns will he have hit
Feliz [49]

Answer:

if it's 18 home runs in 9 baseball games

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to prove if you're right (9×2=18)

if it's 11 baseball games then 11×2=22

Hope It Helps ☺️

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3 years ago
Whats the square root of 15?
lapo4ka [179]

Answer:

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Step-by-step explanation:

8 0
2 years ago
Noor brought 21 sheets of stickers. She gave 1/3 of a sheet to each of the 45 students at recess. She wants to give teachers 1 1
Tamiku [17]

Answer:

\frac{3}{2}t+15\leq 21

Step-by-step explanation:

Let t represent the number of teachers.

We have been given that Noor gave 1/3 of a sheet to each of the 45 students at recess.

Let us find the number of sheets given to students by Noor by multiplying the total number of students by the part of sheet given to each student.

\text{Number of sheets given to 45 students}=45\times \frac{1}{3}

\text{Number of sheets given to 45 students}=15

So, Noor gave 15 sheets to 45 students.

We have been given that Noor wants to give 1\frac{1}{2}=\frac{3}{2} sheet to each teachers, so the number of sheets given to t teachers will be \frac{3}{2}t.

As Noor has bought 21 sheets, so the number of sheets given to students and t teachers will be less than or equal to 21.

We can represent this information in an inequality as:

\frac{3}{2}t+15\leq 21

Therefore, the inequality \frac{3}{2}t+15\leq 21 represents the number of teachers ,t, Noor could give sheets of stickers too.

6 0
4 years ago
Can somebody please help m eits 9th grade math im so confused !
prisoha [69]

Answer:

Option 3: (5, 1)

Step-by-step explanation:

There are several ways of solving for systems of linear equations, either through graphing, substitution, or elimination.  

The graphing method is the easiest, as you only need to plot points on the graph using the y-intercepts and the slopes.  

I will be demonstrating the <u>graphing method</u>.  

Given the systems of linear equations:  

Equation 1:  y = x - 4

where the <u>slope</u>, <em>m</em> = 1, and <u>y-intercept </u>(0, -4).

Equation2: y = -x + 6

where the <u>slope</u>, <em>m </em>= -1, and <u>y-intercept</u> (0, 6).

The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b).

<h3>Graphing Instructions:</h3>

For Equation 1, plot the y-intercept, (0, -4) on the graph. Then use the <u>slope</u>, m = 1 (rise 1 unit, run 1 unit) to plot other points on the graph. Repeat this process until you have enough points to connect a line with.  

Repeat these same procedures for graphing Equation 2, start by plotting its y-intercept at (0, 6), and its slope, m = -1 (down 1 unit, run 1 unit).

<h3>Solution: </h3>

The intersection of both lines occurs at point, (5, 1), which is solution to the given systems of linear equations.  Therefore, the correct answer is the third option, (5, 1).

Attached is the screenshot of the graphed systems of linear equations, where it shows the point of intersection at (5, 1).  

5 0
3 years ago
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