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Mrrafil [7]
4 years ago
6

What equation could represent the situation?

Mathematics
1 answer:
tensa zangetsu [6.8K]4 years ago
3 0
(4.5c) - $0.55 = $3.32
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If total revenue is 3000, cost of goods 1500, and total selling expense is 500; what is the profit for the business
Mrrafil [7]
. If total Revenue is $3000, Cost of Goods is $1500, and total Selling Expense is $500 Question: what is the Profit for the business= The total revenue is 3 000 dollars The expenses =1 500 dollars for gold's costs= 500 dollars for selling expenses.Now, let's add the expenses and subtract it to the total earnings= 1 500 dollars + 500 dollars = 2 000 dollars
Now, let's subtract=3 000 dollars - 2 000 dollars = 1 000 dollars Thus, his profit is 1 000 dollars


5 0
4 years ago
Read 2 more answers
I don’t quite understand this
ExtremeBDS [4]
A. (-5, 6), (2,5), (-1,1)

7 0
3 years ago
Bowling cost $2 to rent shoes,plus $5 per game. Mini golf cost $5 to rent a club, plus $4 per game. How many games would be the
zaharov [31]

Answer:

Step-by-step explanation:

Assuming the same number of bowling and mini golf games are played, let x represent the total number of games played, either bowling or mini golf. let y represent the total cost of bowling. Let z represent the total cost of golfing

Bowling cost $2 to rent a club plus $5 per game. It means that the cost, y for x bowling games will be

y = 2 + 5x

Mini golf cost $5 to rent a club, plus $4 per game. It means that the cost, y for x mini golf games will be

z = 5 + 4x

For the total cost to be the same, we will equate both equations(y = zl

2 + 5x = 5 + 4x

5x - 4x = 5 - 2

x = 3

There would be 3 games before total cost would be the same

4 0
3 years ago
Read 2 more answers
How do you solve these two equations? Please Help!!<br>y = 2x + 160 <br>y = - 3x + 208
Archy [21]
Their are 2 main methods of solving 2 equations with 2 variables:
1) SUBSTITUTION
2) ELIMINATION
I'll show you both:

1) y = 2x + 160
y = - 3x + 208
plug what y is equal to in 1st equation into the y of the 2nd:
2x + 160 = -3x + 208
2x + 3x + 160 = -3x + 3x + 208
5x + 160 -160 = 208 - 160
5x = 48
5x/5 = 48/5
x = 48/5 = 9 3/5
now plug that x into either one of the original equations: y = -3x + 208 = -3(48/5) + 208
y = -144/5 + 208 = 1040/5 - 144/5 = 896/5
y = 179 1/5

2) add the whole equations together so as to cancel out one of the variables:
I'm choosing to eliminate the y, so we need y-y to remove the y's, I'll multiply the whole 2nd equation by -1 to make that -y
-1 (y = - 3x + 208)
-y = 3x - 208
So set it up like:
y = 2x + 160
-[y = 3x - 208]
---------------------
0 = 5x - 48
0+48 = 5x -48 +48
5x = 48
5x/5 = 48/5
x = 48/5
plug that x value into one of the original equations: y = 2x + 160 = 2(48/5) + 160
y = 96/5 + 160 = 96/5 + 800/5 = 896/5
y = 179 1/5

SO WE GOT THE SAME VALUES BOTH WAYS.
WHEN YOU SEE FUTURE PROBLEMS LIKE THESE, SOME WILL BE QUICKER BY ELIMINATION AND OTHERS BY SUBSTITUTION

6 0
4 years ago
What is f(3+h)? if f(x)=x^2 +3x+5​
VladimirAG [237]

Answer:

H^2+9H+23

Step-by-step explanation:

f(3+h)=(3+H)^2+3*(3+H)+5

       =9+6H+H^2+9+3H+5

       =H^2+9H+23

4 0
3 years ago
Read 2 more answers
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