Answer:
- f'(1) exists: f'(1) = -2
- f'(0) DNE
Step-by-step explanation:
<h3>a)</h3>
The function is continuous for x > 0 . The derivative is defined on that interval and is equal to ...
f'(x) = -2x . . . . . for x > 0
Then at x = 1, the derivative is ...
f'(1) = -2(1)
f'(1) = -2
__
<h3>b)</h3>
The function has a jump discontinuity at x=0, so the derivative does not exist at that point. A condition for the existence of the derivative is that the function is continuous at the point of interest.
The question is which figure shows ∠ POQ.
The answer is the option A.
Justification:
The notation ∠ POQ means angle POQ. And that means:
1) the vertex of the angle is the point O (this is the letter at the center of the name).
2) The sense of the measure is from P to Q counter clockwise.
That is what the figure A shows.
The figue B shows ∠ OQP, the figure C shows ∠QPR, and the figure D shows ∠QRP
First do 8 + 4 which is 12
Next do 12 times 2 which is 24
Final step is to do 24 divided by 1 which gets you 24
The answer is 24.
9.3333333333333333333333..............
or
-
9.33
Answer:
x = 17
Step-by-step explanation:
1) Make the bases the same then rewrite.
4 = 2²
2^2(2x - 5) = 2^3x + 7
2) Since the bases are the same, set the exponents equal to each other.
2(2x -5) = 3x + 7
4x - 10 = 3x + 7
4x - 3x = 7 + 10
x = 17
