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Contact [7]
3 years ago
14

The population of a deer in a forest was measured to be 1,537 in the year 2010. If the population increased by a steady 4% per y

ear, which of the following calculations would predict its population in 2013
Mathematics
1 answer:
romanna [79]3 years ago
8 0
Hi there
The formula is
P=A (1+r)^t
P population in 2013. ?
A population in 2010 (1537)
R growth rate 0.04
T time 2,013−2,010=3 years
So
P=1,537×(1+0.04)^(3)
P=1,728.9 round your answer to get
P=1729

Hope it helps
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add 7. double the result. subtract 8. divide by 2. su tract the orginial selected number 1st nuber is 3 second number is 4 the t
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Hi,


The equation looks like this...

n + 7 \times 2 - 8 \div 2 \\ 3 + 7 \times 2 - 8 \div 2 = 3 + 14 - 4 = 13 \\ 4 + 7 \times 2 - 8 \div 2 = 4 + 14 - 4 = 14 \\ 9 + 7 \times 2 - 8 \div 2 = 9 + 14 - 4 = 19 \\ 12 + 7 \times 2 - 8 \div 2 = 12 + 14 - 4 = 22

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3 years ago
What is the circumstance of the circle
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Which statement about an input/output table is true?
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Explain the error a student is asked to find when the value of an investment of $5200 is an account that earns 4.2% annual inter
zloy xaker [14]

We are given the following information

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The student uses the following model

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The general formula for compound interest is given by

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As you can see, the number of compoundings is incorrect (3 vs 4)

The interest rate is also incorrect.

Let us substitute the given values into the above formula

\begin{gathered} V(t)=P(1+\frac{r}{n})^{nt} \\ V(t)=5200(1+\frac{0.042}{4})^{4\cdot27.7} \\ V(t)=5200(1+0.0105)^{110.8} \\ V(t)=5200(1.0105)^{110.8} \\ V(t)=\$16543.5^{} \end{gathered}

Therefore, the final amount is approximately $16,543.5

5 0
1 year ago
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