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Contact [7]
3 years ago
14

The population of a deer in a forest was measured to be 1,537 in the year 2010. If the population increased by a steady 4% per y

ear, which of the following calculations would predict its population in 2013
Mathematics
1 answer:
romanna [79]3 years ago
8 0
Hi there
The formula is
P=A (1+r)^t
P population in 2013. ?
A population in 2010 (1537)
R growth rate 0.04
T time 2,013−2,010=3 years
So
P=1,537×(1+0.04)^(3)
P=1,728.9 round your answer to get
P=1729

Hope it helps
You might be interested in
josie cast a shadow of 6ft and she is 5 ft 6 in tall. A building cast a shadow of 18 ft at the same time that josie measured her
Debora [2.8K]
Josie's height = 5 ft 6 in. = 5 1/2 ft = 11/2 ft.
Josie's shadow = 6 ft.

Ratio of shadow to height = 6 / 11/2 = 12/11
So, It would be equal to ratio of building's shadow to building's height.

18/x = 12/11
x = 18*11 /12
x = 3*11 / 2
x = 16.5

In short, Your Answer would be 16.5 Feet

Hope this helps!

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3 years ago
Allison counted 56 cars parked in the lot. Eight parking spaces remained empty Plan, solve, and check to find the ratio of empty
Alexeev081 [22]
The ratio is 1:8 for empty to full.
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4 years ago
0.7 is 10 times as much as
Neko [114]
0.7 is 10 times as much as 0.70
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4 years ago
Solve for m  p=2m+2w       what does m=
Alika [10]
p=2m+2w \ \ |-2w \\ \\ p-2w=2m +2w -2w \\ \\ p-2w =2m \ \ |:2 \\ \\m=\frac{p}{2}-\frac{2w}{2}\\ \\m=\frac{p}{2}-w


8 0
3 years ago
Write the equation for the parabola that has x− intercepts (−2,0) and (4,0) and y− intercept (0,4).
seropon [69]

Answer:

y = -\frac{1}{2}(x^2-2x-8)

Simplified it is y=-\frac{1}{2}x^2+x+4

Step-by-step explanation:

The x-intercepts of a parabola form the factors of the equation. Since the x -intercepts are (-2,0) and (4,0) then the factors are (x+2) and (x-4). Factors are pieces which multiply to make the equation.

y=(x+2)(x-4)\\y=x^2+2x-4x-8\\y=x^2-2x-8

This is the standard form of the parabola ax^2+bx+c. Since the y-intercept of the parabola is (0,4) then a number must also be multiplied to it

y=a(x^2-2x-8)

We find a by plugging in x=0 and y=4.

4=a(0^2-2(0)-8)\\4=a(0-0-8)\\4=a(-8)\\\frac{4}{-8} = a\\\frac{-1}{2} = a

So the equation is y = -\frac{1}{2}(x^2-2x-8).

When simplified it is y=-\frac{1}{2}x^2+x+4


3 0
3 years ago
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