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joja [24]
3 years ago
11

What is the answer to 15 divided by 1 2/3

Mathematics
1 answer:
sveticcg [70]3 years ago
4 0
Fractions -_- lol 

okay so 15 divided by 1 2/3 is 9 
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How are ∠1 and ∠2 related
andreyandreev [35.5K]

Answer:

  • D. They are adjacent

Step-by-step explanation:

Angles 1 and 2 have common side, so they are adjacent. They are not making a right or straight angle.

Correct choice is D

7 0
2 years ago
Is V <br> 5 rational or irrational
madreJ [45]

Answer:

it's a whole number

Step-by-step explanation:

it's a whole number

4 0
2 years ago
Find the slope of every line that is parallel to the line on the graph.​
melamori03 [73]

Answer:

-1/5

Step-by-step explanation:

What are parallel lines?

Lines that are parallel never touch. They can extend infinitely and they will still never touch. In order for this to happen the slope of the two lines must be the same. So if we want to find the slope of every line that is parallel to the line on the graph, we simply find the slope of the line of the graph.

Finding the slope

We can find the slope using the following formula:

Slope=\frac{y_2-y_1}{x_2-x_1}

Where the x and y values are derived from any given points on the line (x1,y1) and (x2,y2)

Here the given points are (-5,-1) and (0,-2)

So we have (x1,y1) = (-5,-1) meaning x1 = -5 and y1 = -1

We also have (x2,y2) = (0,-2) meaning x2 = 0 and y2 = -2

Now we plug these values into the formula

Recall formula : Slope=\frac{y_2-y_1}{x_2-x_1}

==> Plug in x1 = -5 , y1 = -1 , x2 = 0 and y2 = -2

Slope=\frac{-2-(-1)}{0-5}

==> simplify numerator and denominator

slope = \frac{1}{-5}

So the slope of the line is -1/5

This means the slope of any parallel line to that line would also have a slope of -1/5

8 0
2 years ago
How many groups of 10 are there in 230?​
Ivan

Answer:

23

Step-by-step explanation:

230/10=23

5 0
2 years ago
Read 2 more answers
1 pt) find the average rate of change of the function over the given intervals. h(t)=\cot (t);
blondinia [14]

\text{Consider the function}\\&#10;\\&#10;h(t)=\cot(t) \text{ on the interval }\left [ \frac{\pi}{4}, \ \frac{3\pi}{4} \right ]\\&#10;\\&#10;\text{we know that the average rate of change of a funtion f(x) over the }\\&#10;\text{interval [a, b] is given by}\\&#10;\\&#10;f_{avg}=\frac{f(b)-f(a)}{b-a}\\&#10;\\&#10;\text{so using this, the average rate of change of the given function is}

h_{avg}=\frac{h\left ( \frac{3\pi}{4} \right )-h\left ( \frac{\pi}{4} \right )}{\frac{3\pi}{4}-\frac{\pi}{4}}\\&#10;\\&#10;=\frac{\cot \left ( \frac{3\pi}{4} \right )-\cot \left ( \frac{\pi}{4} \right )}{\frac{3\pi-\pi}{4}}\\&#10;\\&#10;=\frac{(-1)-(1)}{\frac{2\pi}{4}}\\&#10;\\&#10;=\frac{-2}{\frac{\pi}{2}}\\&#10;\\&#10;\text{Average rate of change of function}=\frac{-4}{\pi}

6 0
3 years ago
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