Find the LCM for 5,9
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<span>In statistics, an outlier is an observation point that is distant from other observations.
Given the points
15, 23, 24, 26, 27 and 35
Notice, that the points 15 and 35 are distance from the other points and hence are outliers.
The mean of the observations including the outliers is given by
The mean of the observations without the outliers is given by
Therefore, </span>when <span>the outliers are removed, the mean remains the same.</span>
Given the points
15, 23, 24, 26, 27 and 35
Notice, that the points 15 and 35 are distance from the other points and hence are outliers.
The mean of the observations including the outliers is given by
The mean of the observations without the outliers is given by
Therefore, </span>when <span>the outliers are removed, the mean remains the same.</span>
Mean = 12000
Standard Deviation = 2000
We have to find how many standard deviations is 14,500 away from the mean.
This can be achieved by calculating the z-score
Z-score tells us how many standard deviations above or below is a sample value from the mean. A positive z value shows, sample value is above the mean.
z score can be calculated as = (Sample Value - Mean )/Standard Deviation)
So,
Z-score =
This means, 14,500 is 1.25 standard deviations above the mean value 12,000.
Standard Deviation = 2000
We have to find how many standard deviations is 14,500 away from the mean.
This can be achieved by calculating the z-score
Z-score tells us how many standard deviations above or below is a sample value from the mean. A positive z value shows, sample value is above the mean.
z score can be calculated as = (Sample Value - Mean )/Standard Deviation)
So,
Z-score =
This means, 14,500 is 1.25 standard deviations above the mean value 12,000.