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Ad libitum [116K]
3 years ago
12

A sum of money was shared between George and Benjamin in a ratio of 3:4. if the sum of money was $56.00, how much did George get

??
​
Mathematics
1 answer:
dybincka [34]3 years ago
8 0

None  cause i got it from him :D

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A = 1, b = 5, c = 4 <br> a = 2, b = 1, c = -21
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A

Step-by-step explanation:

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Yolette charges $12.75 for a manicure and $19.50 for a pedicure. Yolette did 7 manicures and 4 pedicures each day for 5 days. Ho
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12.75*7=89.25
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Estimate the quotient: 16 3/4 divided by 4 2/3. Show your work.
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Answer:

Step-by-step explanation:

First turn them into improper fractions.

16 3/4 ----> 67/4

4 2/3 -----> 14/3

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Solve the system. If there is more than one solution, write the general solution. x + y - 2z = 9 3x + y + 2z = 15 x - 5y + 22z =
Margaret [11]

Answer:

<h2>x = (12-k)/2, y = k, z = (k-6)/4 </h2>

Step-by-step explanation:

Given the system of equation

x + y - 2z = 9 ... 1

3x + y + 2z = 15 ...2

x - 5y + 22z = -27... 3

First let us reduce the system of equation into two with two unknowns.

Subtracting 1 from 3

y-(-5y) + (-2z-22z) = 9-(-27)

y+5y + (-24z) = 9+27

6y-24z = 36 ... 4

Multiplying equation 1 by 3 and subtracting from equation 2

3x + 3y - 6z = 27

3x + y + 2z = 15

On subtracting both;

(3y-y)+(-6z-2z) = 27-15

2y-8z = 12 ... 5

Equating 4 and 5

6y-24z = 36 ... 4

2y-8z = 12 ... 5

Multiplying equation 5 by 3 the equation becomes;

6y-24z = 36 ... 6

6y-24z = 36 ... 7

We can see that equation 6 and 7 are the same;

let y = k

6k - 24z = 36

k - 4z = 6

4z = k-6

z = k-6/4

Substituting y = k and z = k-6/4 into equation 1 to get x

From 1; x + y - 2z = 9 ... 1

x + k -2( k-6/4) = 9

x + k - (k-6)/2 = 9

x = 9+(k-6)/2-k

x = {18+(k-6)-2k}/2

x = (12-k)/2

The solutions to the system of equations are x = (12-k)/2, y = k, z = (k-6)/4 where k is any constant. This shows that the system of equation has infinite solutions.

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