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Volgvan
3 years ago
6

If 4x +2y=200 and 2x+7y=400 how do you solve for x and y

Mathematics
1 answer:
Mandarinka [93]3 years ago
6 0
This is what you call systems of equations. Basically were the two equations cross on a graph is the solution
 
You can solve this multiply ways... Graph, table, Substitution, elimination...

I will choose elimination because it is the easiest for how the equations are set up.

So

4x+2y = 200     2x+7y=400

First I take the second equation and multiply it by 2..
2(2x) + 2(7y)= 2(400)

4x+14y=800 

Now I can just subtract the two equations



  4x+2y = 200
-(4x+14y=800)
____________
-12y=-600

Solve for y

-12y/-12=-600/-12

y=50

Plug back in

4x+2y = 200

4x+2(50)=200
4x+100=200
     -100  - 100
4x=100

4x/4=100/4

x=25

(25,50)

To check if you are correct you can use something like desmos (online graphing tool) and see if (25,50) is were the two lines cross.

You can also use substitution if you prefer.


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3(y+7)+8y plz be spacific and answer correctly, im counting on you. :)
Galina-37 [17]

Answer:

11y + 21

Step-by-step explanation:

mutipily 3 by y + 7 bc 3 is right outside of the parentheis which means to mutipily. Then u get 3y +21 +8y. then simpilfy

7 0
3 years ago
I NEED HELP WITH THIS QUESTION QUICK IT'S VER DIFFICULT FOR ME.
Ivenika [448]

Answer:

The relationship is proportional. The constant of proportionality is 20. It represents how many meters the horse runs per second per second. Equation is d=20t

6 0
3 years ago
What are the domain restrictions of the function f(x) = the quantity of x squared plus 6x plus 9, all over 3x plus 15.
dangina [55]

Answer:

x = - 5

Step-by-step explanation:

Given

f(x) = \frac{x^2+6x+9}{3x+15}

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

solve : 3x + 15 = 0 ⇒ 3x = - 15 ⇒ x = - 5 ← excluded value

Domain x ∈ R , x ≠ - 5

6 0
3 years ago
You plant a rectangular rose garden along the side of your garage. You enclose 3 sides of the garden with 40 feet of fencing. Th
solmaris [256]

Let's assume

length of rectangle =L

width of rectangle =W

You enclose 3 sides of the garden with 40 feet of fencing

so, we get

L+2W=40

now, we can solve for L

L=40-2W

we know that

area of rectangle is

A=L*W

100=L*W

now, we can plug

100=(40-2W)*W

now, we can solve for W

-2W^2+40W-100=0

we can use quadratic formula

W=\frac{-40+\sqrt{40^2-4\left(-2\right)\left(-100\right)}}{2\left(-2\right)}

W=\frac{-40-\sqrt{40^2-4\left(-2\right)\left(-100\right)}}{2\left(-2\right)}

we can take anyone value ..because both are giving positive value

first dimensions:

W=2.929

now, we can find L

L=40-2*2.929

L=34.142

so, length is 34.142feet

width is 2.929 feet

Second dimensions:

W=17.071

now, we can find L

L=40-2*17.071

L=5.858

so, length is 5.858feet

width is 17.071 feet



6 0
3 years ago
Use &gt;,&lt;,=.<br> 0.94___0.49
uranmaximum [27]
0.94>0.49 because 0.94 is the larger number.

5 0
3 years ago
Read 2 more answers
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