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3 years ago

What are the domain restrictions of the function f(x) = the quantity of x squared plus 6x plus 9, all over 3x plus 15.

Mathematics

1 answer:

dangina [55]3 years ago

6 0

Answer:

x = - 5

Step-by-step explanation:

Given

f(x) = $\frac{x^2+6x+9}{3x+15}$

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

solve : 3x + 15 = 0 ⇒ 3x = - 15 ⇒ x = - 5 ← excluded value

Domain x ∈ R , x ≠ - 5

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3 years ago

Points J and K are midpoints of the sides of triangle FGH. Triangle F G H is cut by lines segment J K. Point J is the midpoint o

anastassius [24]

Answer:

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3 years ago

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ch4aika [34]

Answer: Option 1

Step-by-step explanation:

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$sf=\frac{12cm}{4cm}\\sf=3$

2. Then the scale factor of the volumes is:

$sf_v=3^{3}\\sf_v=27$

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Feliz [49]

Answer: Bottom-Right corner
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Explanation:

What you do is go through each of the answer choices, plot the points, and see which give you a right triangle. A right triangle has one 90 degree angle.

The upper-left choice leads to an obtuse triangle, so we can cross that off the list. It turns out that the other choices lead to right triangles.

The upper-right choice has a hypotenuse of roughly 11.18, so that's also eliminated

The bottom-left choice has a hypotenuse of 10.82, which means we cross that off the list

The bottom-right choice has a hypotenuse of 15, so we found the answer

Note: you use the distance formula to find the length of the hypotenuse. The distance formula is
d = sqrt((x1-x2)^2+(y1-y2)^2)

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