3 years ago

What are the domain restrictions of the function f(x) = the quantity of x squared plus 6x plus 9, all over 3x plus 15.

Mathematics

1 answer:

dangina [55]3 years ago

6 0

Answer:

x = - 5

Step-by-step explanation:

Given

f(x) = $\frac{x^2+6x+9}{3x+15}$

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

solve : 3x + 15 = 0 ⇒ 3x = - 15 ⇒ x = - 5 ← excluded value

Domain x ∈ R , x ≠ - 5

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