The Poisson distribution defines the probability of k discrete and independent events occurring in a given time interval.
If λ = the average number of event occurring within the given interval, then
For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is
The distribution is graphed as shown below.
Answer:
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.
Answer:
where is the graph if you can put it i will give you the answer
Step-by-step explanation:
K well uh i don't know what u meant but the 4th one i think so u
Your answer is C I’m sure about that!
Data for the question :
102.05 99.85 112.3 97.15 111.23 105.37 105.64 106.5 102.97 107.82 106.36 111.24 107.28 114.14 106.28 106.96 98.25 111.55 107.75 101.02 101.12 97.7 97.66 100.54 115.77 112.91 111.04 112.15 102.87 101.14 107.13 108.56 109.56 103.57 108.68 104.59 116.74 116.22 100.22 103.97 111.2 109.34 115.78 101.59 107.93 104.23 96.25 103.84 102.47 102.96 99.26 101.42 108.58 107.69 99.88 102.71 111.25 99.4 117.04 106.35 110.44 102.34 107.25 107.63 105.2 109.14 115.54 101.51 108.49 112.32 109.27 97.54 102.46 105.94 109.42 111.05 102.63 106.99 102.03 108.84 118.8 108.64 95.35 105.47 104.45 102.15 111.4 108.27 104.82 108.4 109.05 116.11 103.7 121.2 99.62 102.81 109.56 103.35 113.02 103.79
Answer:
Range = 25.35
Variance = 29.46
Standard deviation = 5.43
The variation in price of Prozac is high
Step-by-step explanation:
The range of the data :
Maximum - Minimum.
121.2 - 95.35 = 25.35
The variance, s :
s² = Σ(X - m²) / n - 1
Mean, m = Σx / n
X = individual data point
m = mean of data
n = sample size
Using a calculator of save time and ensure accuracy :
s² = 29.45522
The standard deviation, s
s = sqrt(variance)
s = sqrt(s²)
s = sqrt(29.45522)
s = 5.42726.
The range, variance and standard deviation, all measure the degree of variation in a dataset. The values of these statistical measure obtain for the price of 1 product across different pharmaceutical stores, suggests thatvthe variation in price is high;
With a range of about 25.35 and standard deviation of 5.43
