Answer:
∠Q = 53.13 degrees
Step-by-step explanation:
Given that ∆PQR, ∠P = 90degrees , this means that the triangle is a right angled triangle
Hence using the notation
SOH CAH TOA
where S is sine, C is cosine, T is tangent and O, A and H represents the size of the opposite, adjacent and hypotenuse sides
Considering ∠Q and the given sides
PR=16cm is the opposite side,
PQ= 12 cm is the adjacent side hence we use TOA
Tan Q = 16/12 =
Q = Arc tan 16/12
= 53.13 degrees
4x = 32 - 2x
Add -2x (or subtract 2x) from each side
2x = 32
Divide both sides by 2
x = 16
ST = 1/2 (RV) = VQ = 6
answer
ST = 6
hope it helps
2/3 - 1/4 ... let's find the common numbers 12 so new numbers would be 8/12 and 3/12 aka 11/12 + .. anyways it's 11/12 plus 2/3 x
Answer:
Step-by-step explanation:
f(x) is quadratic function and g(x) is linear (since AP in the right column).
<u>Find the equation of the function f(x), use the points on the graph:</u>
- c = 5 as the y-intercept is (0, 5)
- a(-1)² + b(-1) + 5 = 0 ⇒ a + 5 = b
- a(5²) + b(5) + 5 = 0 ⇒ 25a + 5b + 5 = 0 ⇒ 25a + 5a + 25 + 5= 0 ⇒ a = -1 ⇒ b= 4
<u>The function is:</u>
Find the equation of g(x)
<u>Find the slope of g(x):</u>
- m = (1 - 7)/(-1 + 4) = -2
<u>Use (-4, 7) to find its equation:</u>
- y - 7 = -2(x + 4)
- y = -2x + 7 - 8
- y = -2x - 1
<h3>See the required comparison below</h3>
<u>The y-intercepts:</u>
- f(x) ⇒ 5,
- g(x) ⇒ -1
- -5 < - 1
<u>Values at x = 3:</u>
- f(3) = -3² + 4(3) + 5 = 8
- g(3) = -2(3) - 1 = - 7
- 8 > 7
<u>Average rate of change in the interval [2,5]:</u>
- f(x) ⇒ (0 - 9)/(5 - 2) = -3
- g(x) ⇒ (-11 + 5)/ (5 - 2) = -2
- -3 < -2
<u>Max of function in the interval [-5, 5];</u>
- f(x) ⇒ 9, vertex of the function
- g(x) ⇒ g(-5) = -2(-5) - 1 = 9, taken the least point of x as it is a decreasing function
- 9 = 9
