2 years ago

PLEASE HELP ASAP 25 PTS

Mathematics

1 answer:

stepan [7]2 years ago

6 0

Answer:

2.810 log3(21.903)

Step-by-step explanation:

log5(92) = 2.810

To change bases

logb(a) = logc(a) / logc(b)

where c is the new base and b is the old base

log5 (92) = log 3(92)/log3(5)

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A Geometric series has a first term of 4 and a common ratio of 6. what formula is equivalent to the partial sum of the first n t

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$\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=4\\
r=6
\end{cases}
\\\\\\
S_n=4\left( \cfrac{1-6^n}{1-6} \right)\implies S_n=4\left( \cfrac{1-6^n}{-5} \right)$