Question

A right triangle has coordinates A(6, 0), B(0, 0), and C(0, 8). What is the perimeter of the triangle?

Answer 1

Answer:

C

Step-by-step explanation:

From the given coordinates

A(6, 0), B(0, 0) then AB = 6 - 0 = 6

B(0, 0), C(0, 8) then BC = 8 - 0 = 8

To calculate AC use Pythagoras' theorem on the right triangle formed

AC² = AB² + BC² = 6² + 8² = 36 + 64 = 100

Take the square root of both sides, hence

AC = $\sqrt{100}$ = 10

Perimeter = AB + BC + AC = 6 + 8 + 10 = 24 → C