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3 years ago

A right triangle has coordinates A(6, 0), B(0, 0), and C(0, 8). What is the perimeter of the triangle?

Mathematics

1 answer:

dimulka [17.4K]3 years ago

5 0

Answer:

Step-by-step explanation:

From the given coordinates

A(6, 0), B(0, 0) then AB = 6 - 0 = 6

B(0, 0), C(0, 8) then BC = 8 - 0 = 8

To calculate AC use Pythagoras' theorem on the right triangle formed

AC² = AB² + BC² = 6² + 8² = 36 + 64 = 100

Take the square root of both sides, hence

AC = $\sqrt{100}$ = 10

Perimeter = AB + BC + AC = 6 + 8 + 10 = 24 → C

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3 years ago

PLEASE ANSWER WITH AN EXPLANATION! THANK YOU

lubasha [3.4K]

Answer:

$\large\boxed{A=153\ cm^2}$

Step-by-step explanation:

<em>Look at the picture.</em>

We have

square with side length a = 9

trapezoid with base lengths b₁ = 9 and b₂ = 6 and the height length h = 6

right triangle with legs lengths l₁ = 3 + 6 = 9 and l₂ = 6

The formula of an area of a square

$A=a^2$

Substitute:

$A_I=9^2=81\ cm^2$

The formula of an area of a trapezoid:

$A=\dfrac{b_1+b_2}{2}\cdot h$

Substitute:

$A_{II}=\dfrac{9+6}{2}\cdot6=\dfrac{15}{2\!\!\!\!\diagup_1}\cdot6\!\!\!\!\diagup^3=(15)(3)=45\ cm^2$

The formula of an area of a right triangle:

$A=\dfrac{l_1l_2}{2}$

Substitute:

$A_{III}=\dfrac{(9)(6)}{2}=\dfrac{54}{2}=27\ cm^2$

The area of the shape:

$A=A_I+A_{II}+A_{III}\\\\A=81+45+27=153\ cm^2$

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4 years ago

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Step-by-step explanation:

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where me = number of months

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= 4500 - 350m

= 4500 - 350(4)

= 4500 - 1200

= 3300

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