Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
Answer:
<h2>x=2</h2><h2>y=4</h2>
Step-by-step explanation:
5x-y=6
2x+y=8
add them up
7x=14
divide by 7 to get x
x=2
fit it into both equation
y=4
Decimals are a number and a dot and more numbers
Answer:
Please refer to the attached graph
Step-by-step explanation:
Knowing the following:
X = amount of money donated to the city youth fund
Y = amount of money donated to the educational growth foundation
We can write the statements in form of equations:
"Will donate up to $500, the money will be divided between two charities"
(a)
"The amount donated to the educational growth foundation to be at least four times the amount donated to the city youth fund"
(b) 
If we graph both equations we can see the area where both conditions are met (see graph attached)
Where the blue line is (a) and the red line is (b)
Shaded area represent all the possible solutions for the donations, for example:
X=100 and Y=400 or
X=50 and Y=200, etc.
substitute 4 as x in both sides of the equation
basically multiply -3/2 by 4