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DerKrebs [107]
3 years ago
9

Define your variable and write an equation that models the cost of each bracelet. X

Mathematics
2 answers:
Alexxandr [17]3 years ago
6 0
Work

<span>X is the price of bracelet

8x + 6 = 54
8x = 54 - 6
8x = 48
x = 48/8
x = 6

Answer

the bracelet cost $6</span>
ipn [44]3 years ago
6 0
Each bracelet should cost 6 dollars.
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What is the length of the unknown leg in the right triangle? A right triangle has a side with length 20 meters, hypotenuse with
galben [10]

The length of the unknown leg of the triangle is 15 m.

<u>Step-by-step explanation:</u>

Length of one leg = 20 m

Length of the hypotenuse= 25m

As it is a right angled triangle we can use pythogoras theorem.

Let the unknown length be y

(20) (20)  + y(y) = (25) (25)

400 + y(y) = 625

y(y) = 225

y = √225

y = 15

The length of the unknown leg is 15 m.

6 0
3 years ago
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What is the solution to q+(-9)=12
Whitepunk [10]
<span><span>
q−9</span>=12

</span>Step 1: Add 9 to both sides.

<span><span><span>q−9</span>+9</span>=<span>12+9

</span></span><span>q=21

</span>Answer:

<span>q=21</span>
7 0
3 years ago
Read 2 more answers
Just Peachy Orchard produced 1100 bushels of peaches last year. This year the owner earned $8800 from sales. He's thinking that
Slav-nsk [51]

Answer:

P(t) ={8*(1.01)^t}

Step-by-step explanation:

The number of bushels produced is given by:

B(t)= 1100(1.1)^t

The owner's income is given by:

S(t) = 8800(1.111)^t

Income is given by the price per unit multiplied by the number of units sold. Therefore, the price function can be represented as:

P(t) =\frac{S(t)}{B(t)} \\P(t) =\frac{8800(1.111)^t}{1100(1.1)^t} \\P(t) =\frac{8*1100(1.1)^t*(1.01)^t}{1100(1.1)^t}\\P(t) ={8*(1.01)^t}

3 0
3 years ago
Write an equation that is perpendicular to and 3x+y=3 whose y-intercept 5. Anyone please help me, no link just explain how to do
Liula [17]

Answer:

y = \frac{1}{3}x + 5

Step-by-step explanation:

By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other:  m = - \frac{1}{m_{2} }, or equivalently, m_{1} * m_{2} = -1.

Given our linear equation  3x + y = 3  (or y = -3x + 3):

We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is \frac{1}{3}.

To test whether this is correct, we can take first slope,  m_{1} = -3,  and multiply it with the negative reciprocal slope m_{2} = \frac{1}{3} :

m_{1} * m_{2} = -1

-3 * \frac{1}{3}  = -1

Therefore, we came up with the correct slope for the other line, which is  \frac{1}{3}.

Finally, the y-intercept is given by (0, 5). Therefore, the equation of the line that is perpendicular to 3x + y = 3 is:

y = \frac{1}{3}x + 5

7 0
3 years ago
Need help finding the x, y, and z. please and thank you
Reptile [31]

The first step in any problem is to look at what you are given. When solving systems of linear equations, it is often helpful to eliminate one or more of the variables by adding or subtracting a multiple of one equation with a multiple of another. It is convenient when at least one of the multipliers is 1.

Here, we can cancel the y-terms in the 2nd and 3rd equations simply by adding them together. This gives

... (5x +y -4z) +(-3x -y +5z) = (41) +(-45)

... 2x +z = -4 . . . . simplified

Likewise, we can add 3 times the second equation to the first to cancel y in that sum.

... 3(5x +y -4z) +(2x -3y +z) = 3(41) + (-1)

...15x +3y -12z +2x -3y +z = 123 -1

...17x -11z = 122 . . . . simplified

Now that we have 2 equations in x and z, we can go through the same process. We observe that the coefficient of z is +1 in the first equation and -11 in the second. The means we can cancel the z terms by adding 11 times the first equation to the second:

... 11(2x +z) +(17x -11z) = 11(-4) +122

...22x +17x = 78 . . . . . . simplify a little bit

... x = 78/39 = 2 . . . . . . divide by 39

From above, we find

... z = -4 -2x = -4 -2·2 = -8

... y = 41 -5x +4z = 41-5(2) +4(-8) = 41 -42 = -1

The solution is (x, y, z) = (2, -1, -8).

_____

The method of elimination used here will vary with the system of equations. If you want to employ a consistent method, you can use Cramer's Rule, Gaussian elimination, or matrix methods. Since you apparently don't mind help from technology, learning to do this on your graphing calculator can also be a good idea.

4 0
3 years ago
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