Answer:
I believe 7 is the GTF (greatest common factor)
Answer:
See below
Step-by-step explanation:
11 box 1: 12
11 box 2: 101
12 box 1: 80
12 box 2: 80
12 box 3: 80
13 box 1: 16
13 box 2: 16
13 box 3: 76
20 = y + 12
20 - 12 = y + 12 - 12
8 = y
x + 2 = 19
x + 2 - 2 = 19 - 2
x = 17
z - 313 = 176
z - 313 + 313 = 176 + 313
z = 489
Answer:
P(X ≥ 1) = 0.50
Step-by-step explanation:
Given that:
The word "supercalifragilisticexpialidocious" has 34 letters in which 'i' appears 7 times in the word.
Then; the probability of success = 7/34 = 0.20588
Using Binomial distribution to determine the probability; we have:

where;
x = 0,1,2,...n and 0 < β < 1
and x represents the number of successes.
However; since the letter is drawn thrice; the probability that the letter "i" is drawn at least once can be computed as:
P(X ≥ 1) = 1 - P(X< 1)
P(X ≥ 1) = 1 - P(X =0)
![P(X \ge 1) = 1 - \bigg [ {^3C__0} (0.21)^0 (1-0.21)^{3-0} \bigg]](https://tex.z-dn.net/?f=P%28X%20%5Cge%201%29%20%3D%20%201%20-%20%5Cbigg%20%5B%20%7B%5E3C__0%7D%20%280.21%29%5E0%20%281-0.21%29%5E%7B3-0%7D%20%5Cbigg%5D)
![P(X \ge 1) = 1 - \bigg [ 1 \times 1 (0.79)^{3} \bigg]](https://tex.z-dn.net/?f=P%28X%20%5Cge%201%29%20%3D%20%201%20-%20%5Cbigg%20%5B%201%20%5Ctimes%201%20%280.79%29%5E%7B3%7D%20%5Cbigg%5D)
P(X ≥ 1) = 1 - 0.50
P(X ≥ 1) = 0.50
Answer:
C
Step-by-step explanation:
considering you need at least 6 people, you would either need 6 or more, so 6 or greater, so C