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kozerog [31]
2 years ago
13

Can someone tell me how to do this? I probably learned this but fractions are really confusing...

Mathematics
1 answer:
Stels [109]2 years ago
6 0
So,

17/3 is an improper fraction.

We can immediately see that there are more that 5 3's in the fraction. That uses 15 "3's".
There are 2 more thirds, so the mixed form is

5 2/3

5 2/3 is less than 8, so that is the answer.
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Please help with this question​
Sergio039 [100]
The answer would be x=3
7 0
2 years ago
If h(x)=(fog)(x) and h(x)=³√x+3, find g(x) if f(x) =³√x+2
ipn [44]

Answer:

g(x)=x+1

The problem:

Find g(x) if h(x)=(f \circ g)(x),

h(x)=\sqrt[3]{x+3}, and

f(x)=\sqrt[3]{x+2}.

Step-by-step explanation:

h(x)=(f \circ g)(x)

h(x)=f(g(x))

Replace x in f(x)=\sqrt[3]{x+2} with g(x) since we are asked to find f(g(x)):

\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}

\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}

This implies that x+1=g(x)

Let's check:

(f \circ g)(x)

f(g(x))

f(x+1)

\sqrt[3]{(x+1)+2}

\sqrt[3]{x+1+2}

\sqrt[3]{x+3}  which is the required result for h(x).

6 0
2 years ago
BRAINLIEST<br>x + 4 &gt; 8. If you need to solve for x, what's the first step?
Darina [25.2K]

Answer:

the first step is subtract 4 from both sides

x + 4 > 8

x + 4 - 4 > 8 - 4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the rational roots f(x) =3x3+ 2x2 + 3x + 6
Ann [662]

The rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

<h3>How to determine the rational root of the function f(x)?</h3>

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

For a function P(x) such that

P(x) = ax^n +...... + b

The rational roots of the function p(x) are

Rational roots = ± Possible factors of b/Possible factors of a

In the function f(x), we have:

a = 3

b = 6

The factors of 3 and 6 are

a = 1 and 3

b = 1, 2, 3 and 6

So, we have:

Rational roots = ±(1, 2, 3, 6)/(1, 3)

Split the expression

Rational roots = ±(1, 2, 3, 6)/1 and ±(1, 2, 3, 6)/3

Evaluate the quotient

Rational roots = ±(1, 2, 3, 6, 1/3, 2/3, 1, 2)

Remove the repetition

Rational roots = ±(1, 2, 3, 6, 1/3, 2/3)

Hence, the rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

The complete parameters are:

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

The rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

Read more about rational roots at

brainly.com/question/17754398

#SPJ1

4 0
1 year ago
A circular table top has a radius of 60cm. A force of 650N is applied to the whole table top. Calculate the pressure in N/m to 4
ikadub [295]

Answer:

i hope its understood....

8 0
2 years ago
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