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3 years ago

A is the midpoint of JM . If JA = 6x - 4 and JM = 9x + 13, find AM. The length of AM is

Mathematics

2 answers:

bagirrra123 [75]3 years ago

8 0

Answer:

AM = 38

Step-by-step explanation:

Since A is the midpoint of JM, then

JA = AM = 6x - 4 , and

JA + AM = JM ← substitute values

6x - 4 + 6x - 4 = 9x + 13, that is

12x - 8 = 9x + 13 ( subtract 9x from both sides )

3x - 8 = 13 ( add 8 to both sides )

3x = 21 ( divide both sides by 3 )

x = 7

Hence

AM = 6x - 4 = (6 × 7) - 4 = 42 - 4 = 38

MatroZZZ [7]3 years ago

4 0

Answer:

$38 = AM$

Step-by-step explanation:

Since A is the MIDPOINT of JM, AM is equivalent to JA, therefore you double up 6x - 4 and set that equal JM at 9x + 13:

$9x + 13 = 2[6x - 4] \\ \\ 9x + 13 = 12x - 8$

-12x - 12x

______________________

−3x + 13 = −8

- 13 - 13

______________

−3x = −21

____ ____

−3 −3

$7 = x$

[Plug this back into the equation of 6x - 4 to get the length of 38]

I am joyous to assist you anytime.

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Need help! Does anyone know how to do this type of math? (It's geometry)

mart [117]

Answer:

Step-by-step explanation:

refer the attachment

to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that tangents which meet at the same point are equal that is being said

FA=AI=17
CH=CG=2.5

since $\rm BA=FA+FB$ and it's given that FA and BA are 17 and 29 FB should be

$\rm 29=17+FB$

therefore,

$FB=29-17=\boxed{12}$

once again by two tangent theorem we acquire:

$FB=BH=\boxed{12}$

As BC=BH+CH,BC is

12+2.5
$\boxed{14.5}$

likewise,AD=AI+DI so,

21=17+DI [AD=21(given) and AI=17 (by the theorem)]

thus,

DI=21-17= $\boxed{4}$

By the theorem we obtain:

DI=DG=4

Similarly,DC=DG+CH therefore,

DC=4+2.5= $\boxed{6.5}$

Now finding the Perimeter of ABCD

$P_{\text{ABCD}}=\text{AB+AD+BC+DC}$

substitute what we have and got

$P_{\text{ABCD}}=\text{29+21+14.5+6.5}$

simplify addition:

$P_{\text{ABCD}}=\boxed{71}$

hence,

the Perimeter of ABCD is 71

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2 years ago

......is an example of

Stolb23 [73]

Answer:

The answer would be 'D'.

Step-by-step explanation:

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I hope this helps!

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PLEASE HELP!!!!! What is the value of x in the matrix equation below?

Brums [2.3K]

The given matrix equation is,

$1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]$ .

Multiplying the matrices with the scalars, the given equation becomes,

$\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\$

Adding the matrices,

$\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\$

Matrix equality gives,

$1.5x+y=z\\ 9+4y=z\\ 12+3y=6z\\ 6+2y=2$

Solving the equations together,

$y=-2\\ 3y-1.5x=9\\ -1.5x=9+6\\ x=-10$

We can see that the equations are not consistent.

There is no solution.

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