A is the midpoint of JM . If JA = 6x - 4 and JM = 9x + 13, find AM. The length of AM is
2 answers:
Answer:
Step-by-step explanation:
Since <em>A</em><em> </em>is the MIDPOINT of <em>JM</em><em>,</em><em> </em><em>AM</em><em> </em>is equivalent to<em> </em><em>JA</em><em>,</em><em> </em>therefore you double up <em>6x</em><em> </em><em>-</em><em> </em><em>4</em><em> </em>and set that equal <em>JM</em><em> </em>at <em>9x</em><em> </em><em>+</em><em> </em><em>13</em>:
-12x - 12x
______________________
−3x + 13 = −8
- 13 - 13
______________
−3x = −21
____ ____
−3 −3
[Plug this back into the equation of <em>6x</em><em> </em><em>-</em><em> </em><em>4</em><em> </em>to get the length of 38]
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Answer:
y + 7 = (x + 6)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b ) a point on the line
Here m = and (a, b ) = (- 6, - 7 ) , then
y - (- 7) = (x - (- 6) ) , that is
y + 7 = (x + 6)