Answer:
Option A.
Step-by-step explanation:
12 cm, 17cm, 25 cm
We are given that popularity of television is inversely proportional to its cost.
let us say popularity of television is represented by "P" and cost of television by "T".
We will use a constant "k" to convert the proportionality sign to equal to (=) sign.
Thus forming the equation :

We are given that 15 customers buy a television that cost $1500.
plugging P=15 and T=1500, finding k,

k=15*1500 = 22500
Next we have to find how many customers would buy a television that costs $2500, so here k=22500 and T=2500, plugging this in the equation we have ,

P=9
So there will be 9 customers that buy a television which costs $2500.
Answer:
4 847 575, 389362513
Step-by-step explanation:
is the answer
hope i helped
A random variable x is normally distributed with a mean of 100 and a variance of 25. Given that x = 110, its corresponding z- score is 0.40.
Answer: The given z-score is false.
Explanation: We are given:
Mean,
,
Variance, 



The z-score formula is given below:




Therefore, the z-score corresponding x=100 is 2
Therefore, the given z-score = 0.4 is false.
Answer:
null hypothesis is p=0.41
alternate hypothesis is p<0.41
Sample proportion is 0.36
critical value for a = 0.01 is -2.2326
z-statistic is −1,0166
critical value for the level of significance 0.10 is -1.28155
we fail to reject the null hypothesis in 0.01 significance level.
Step-by-step explanation:
Let p be the proportion of the viewing audience of 11:00PM CBS newscast in the area. Then
: p=0.41
: p<0.41
Sample proportion is 0.36 and critical value (left tailed) for a=0.01 is -2.2326
sample proportion Z-score can be calculated as follows:
z(0.36)=
where
- p(s) is the sample proportion of vieved newscast (0.36)
- p is the proportion assumed under null hypothesis. (0.41)
- N is the sample size (100)
putting the numbers z(0.36)=
=−1,0166
if the level of significance is 0.10 then critical value would be -1.28155.
in 0.01 significance level sample mean is not in the critical region, therefore we fail to reject the null hypothesis.