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kow [346]
3 years ago
14

2. Amy had 0.87 liters of grape juice. Flora had 0.92 liters more. How much

Mathematics
1 answer:
iogann1982 [59]3 years ago
3 0

Answer:

1.79 of cold drink

Step-by-step explanation:

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Local newspaper company wanted to determine if there is a need for a digital version of their newspaper. They sampled 80 of thei
Oksana_A [137]

Answer:

A.) 7:3

B.) Approximately 96,772 people

Step-by-step explanation:

The newspaper company sampled 80 of their subscribers.

56 of the 80 would be interested in the new services.

So, 80 - 56 = 24 people would not be interested in the new service.

The ratio of those interested in the new service to those who are not interested is:

56 : 24 simplified becomes 7 : 3 (We divide 56 and 24 by a common divisor = 8)

If the total number of subscribers for the newspaper is 138,346

The number of subscribers who would be interested in the new service would be:

\frac{7}{10} × 138,246 = 96,772.2 people

Because there are no 0.2 people, we remove the decimal point of the answer and hence;

Approximately 96,772 people would be interested in the new service.

3 0
3 years ago
-3j - (-4) over -6 = 12 j= ? ​
babymother [125]

Answer:

j =76/3

Step-by-step explanation:

-3j -  -4

------------------ = 12

-6

Multiply each side by -6 to clear the fraction

-3j +4

------------------ * -6 = 12 *-6

-6

-3j +4 = -72

Subtract 4 from each side

-3j +4-4 = -72 -4

-3j = -76

Divide each side by -3

-3j/-3 = -76/-3

j = 76/3

5 0
3 years ago
Which of the following gives an example of a set that is closed under addition.
cluponka [151]
I believe the answer is D
4 0
3 years ago
Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
3 years ago
Could ya'll give me a hand on this?
Georgia [21]
I hope this helps you

6 0
3 years ago
Read 2 more answers
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