Answer:
On the 1st Jan 2012 Beth invested some money into a bank account.The account pays 2.5% interest per year.On the 1st Jan 2013 she withdraws £1000.
Step-by-step explanation:
13 she withdraws £1000.On the 1st Jan 2014 she had £17,466 in the account.How much money did Beth originally invest into the account.Please show your method.
Solution
-3b + 11 = -18 + 8b
-3b - 8b = -18 - 11
-11b = -29
b = 29/11
The exponential function models the value v of the car after t years is V = 27000 * (0.93)^t
<h3>How to determine the exponential model?</h3>
The given parameters are:
Initial value, a = $27,000
Depreciation rate, r = 7%
The value of the car is then calculated as:
V = a * (1 -r)^t
Substitute known values
V = 27000 * (1 - 7%)^t
Evaluate the difference
V = 27000 * (0.93)^t
Hence, the exponential function models the value v of the car after t years is V = 27000 * (0.93)^t
Read more about exponential function at:
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9514 1404 393
Answer:
-0.16
Step-by-step explanation:
The 'a' value can be found by looking at the difference between the y-value of a point 1 unit from the vertex, and the y-value of the vertex.
Here, that is a negative fraction of a unit. If we assume the value is a rational number that can be accurately determined from this graph, then we can find it by looking for a point where the graph crosses a grid intersection. It looks like such grid points are (-7, 0) and (3, 0). The vertex is apparently (-2, 4), so the vertex form of the equation is ...
y = a(x +2)^2 +4
Using the point (3, 0), we have ...
0 = a(3 +2)^2 +4 . . . . . fill in the values of x and y
-4 = 25a . . . . . . . . . . subtract 4; next, divide by 25
a = -4/25 = -0.16
