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Elza [17]
3 years ago
6

Write the equation of a line that is perpendicular to y=-2/7x+9 and that passes through the point (4,-6)

Mathematics
1 answer:
stich3 [128]3 years ago
3 0

Answer:

y = 7/2x - 20

Step-by-step explanation:

The slope of a perpendicular line is the opposite reciprocal of the original slope.

-2/7 -> 7/2

Find the new y-intercept.

y = 7/2x + b

-6 = 7/2(4) + b

-6 = 14 + b

-20 = b

y = 7/2x - 20

Best of Luck!

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8 0
3 years ago
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What is an equation of the line that passes through the points (6,−4) and (−6,2)? Put your answer in fully reduced form
katovenus [111]
Y=mx+b
m=slope
b=yintercept
slope=(y1-y2)/(x1-x2)
(x,y)
x1=6
y1=-4
x2=-6
y2=2

(-4-2)/(6-(-6))=-6/12=-1/2
y=-1/2x+b
subsitute one point
(6,-4)
x=6
y=-4
-4=1/2(6)+b
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subtract 3
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Answer:

<h2><u><em>c 5/7</em></u></h2>

Step-by-step explanation:

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