Question

If a disk drive has 8 surfaces and there are 1024 tracks per surface with 256 sectors per track and 512 bytes/sector. What is the capacity of the drive?

Answer 1

Answer:

The capacity of the drive in Gigabytes equals 1.0737 Gbs

Explanation:

Given there are 1024 tracks per surface.

Number of surfaces = 8

Hence number of tracks in 8 surfaces equals $1024\times 8=8192$ tracks

Now it is given that there are 256 sectors per track thus the number of sectors in 8192 tracks equals $8192\times 256=2097152$ sectors

Now it is given that there are 512 bytes per sector thus the number of bytes in 2097152  equals $2097152\times 512=1073741824$ bytes

Converting to gigabytes the capacity of the drive in gigabytes equals 1.0737Gbs