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VladimirAG [237]
3 years ago
14

A 9-year old male castrated Westie presents on emergency after being rescued from a house fire. On presentation, the dog has a r

espiratory rate of 60 breaths per minute with increased inspiratory effort and moderate distress. The dog's mucous membranes are bright red. What is the likely cause of the bright red color of the dog's mucous membranes?
Computers and Technology
1 answer:
satela [25.4K]3 years ago
8 0

Answer:

Carbon Monoxide poisoning

Explanation:

According to my research on studies conducted by various medical professionals, I can say that based on the information provided within the question the most likely cause for this is Carbon Monoxide poisoning. This is a gas very similar to oxygen although it is poisonous to living organisms and very flammable. When inhales displaces oxygen on hemoglobin molecules which then formes carboxyhemoglobin complexes, which causes the mucous membrane to become bright red.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Write a C++ function, smallestIndex, that takes as parameters an int array and its size and returns the index of the first occur
Oduvanchick [21]

Answer:

Explanation:

The code in C++ is written as:

#include <iostream>

using namespace std;

int smallestIndex(int arr[],int size)

{

int min=arr[0],ind=0;

for(int i=0;i<size;i++)

{

if(min>arr[i])

{

min=arr[i];

ind=i;              NOTE: ind serves as a variable that is holding the smallest

}                                   element index of array

 

}

return ind;

}

int main() {

int arr[15];

cout<<"Enter 15 integers: ";

for(int i=0;i<15;i++)

cin>>arr[i];

for(int i=0;i<15;i++)

cout<<arr[i]<<" "<<endl;

int index=smallestIndex(arr,15);

cout<<"The position of the first occurrence of the smallest element in list is: "<<index<<endl;

cout<<"The smallest element in list is: "<<arr[index];

}

OUTPUT:

Enter 15 integers:

4

5

8

4

6

1

2

1

4

5

7

9

5

7

8

4   5  8  4  6  1  2  1  4  5  7  9  5  7  8  

The position of the first occurrence for the smallest element in the list is 5

The smallest element in the list is: 1

7 0
3 years ago
The two fundamental approaches to moving data through a network of links and switches are
olga55 [171]

Answer:Packet and circuit switching

Explanation: Packet switching is the technique through which the data is sent from the source to destination in the form of data packets on dynamic path.It is the time of connectionless switching and route generates for each packet.

Circuit switching is the switching technique having connected path for the sending and receiving of the data.They have well defined and established path for the transmission of data.

Other options are incorrect because they define the terms that are associated with the data that gets transmitted like bandwidth,transmission rate ,packet etc. These options are not the way in which data transmitted or switched.Thus, the correct option is packet and circuit switching.

6 0
3 years ago
Wide area network (WAN) connects multiple networks that are in the same geographical locations.
xeze [42]

Answer:

False.

Explanation:

<em>This is pertaining to LAN or Local Area Network. LAN is a type of network that is consist of one or several networks located in one geographical area or location. Wherein WAN or Wide Area Network is a type of network that is located in different or several geographical area. The basic example of WAN is the Internet. Networks of computers are connected even though they are not wired physically.</em>

5 0
3 years ago
A detective agency is looking to bust an arms sale. According to available intelligence, the sale is likely to happen in one of
Paha777 [63]

Answer:

Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}

H(X)=5.4224 bits per symb

H(X|Y="not C")=0.54902 bits per symb

Explanation:

P(B)=2P(C)

P(A)=2P(B)

But

P(A)+P(B)+P(C)=1

4P(C)+2P(C)+P(C)=1

P(C)=1/7

Then

P(A)=4/7

P(B)=2/7

Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}

iii

If X={A,B,C}

and P(Xi)={4/7,2/7,1/7}

where  Id =logarithm to base  2

Entropy, H(X)=-{P(A) Id P(A) +P(B) Id P(B) + P(C) Id P(C)}

=-{(1/7)Id1/7 +(2/7)Id(2/7) +(4/7)Id(4/7)}

=5.4224 bits  per symb

if P(C)  =0

P(A)=2P(B)

P(B)=1/3

P(A)=2/3

H(X|Y="not C")= -(1/3)Id(I/3) -(2/3)Id(2/3)

=0.54902 bits per symb

4 0
3 years ago
Which of the following help departments organize unique access controls for access to folders and data files within a department
never [62]

Answer:

B. Role-based access controls

Explanation:

Roll-based access control is a way to control access to the network and to data which depends on the position of employees in a department. This way the permission to access information are granted according to roles that are assigned to employees. This type of access control allows access privileges to employees only to the folders and data files which they need in order to perform their tasks and it does not allow them to access the data or information which is not relevant to them. This helps the department to secure the sensitive information and data files and reduces the risk of data breaches.

6 0
3 years ago
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