Hello,
1) we imagine a linear function:
y=ax+b
(1,3)==>3=a+b (1)
(2,6)==>6=2a+b (2)
(2)-(1)==>a=3==>b=3-3=0
So we find y=3x
But (3,11)==>11=3*3 is false ==> no linear function A,B and D are false.
2) we imagine a quadratic function
y=ax²+bx+c
(1,3)==>3=a+b+c (1)
(2,6)==>6=4a+2b+c (2)
(3,11)==>11=9a+3b+c (3)
(3)-(2)==>5a+b=5 (4)
(2)-(1)==>3a+b=3 (5)
(4)-(5)==> 2a=2==> a=1
==> b=5-5*1=0
(1)==>3=1+0+c==>c=2
The quadratic function is y=x²+2
and you have make a mistake in your question!
Answer is C if you change in y=x²+2
Proof:
(4,18) 18=1*4²+0*4+2=16+2=18
Answer:
c 4800/80 =60
Step-by-step explanation:
Answer:
68
Step-by-step explanation:
Since this is an isosceles triangle the bottom 2 angles are equal. So both bottom angles are 56 degrees. The three angles of a triangle add to 180 degrees.
56+ 56+ x = 180
Combine like terms
112 +x =180
Subtract 112 from each side
112-112+x = 180-112
x =68