Don't report what you don't understand
the x value of the vertex of the parabola in form
y=ax^2+bx+c
is -b/2a
given
y=6x^2-72x+220
x value of vertex is -(-72)/(2*6)=72/12=6
xvalue is 6
sub that for x in the equation
y=6(6)^2-72(6)+220
y=216-432+220
y=4
(x,y)
vertex is (6,4)
Answer:
If your looking to solve it, the answer is x=2/15
Step-by-step explanation:
<span>An <span>isosceles trapezoid<span> has
both legs of equal length. LK = MN
Lower base angles are equal. ∠ K = ∠ N
Upper base angles are equal. ∠ L = ∠ M
Opposite angles are supplementary. ∠ K + ∠ M = 180°
If you picture the top LM = 3 moving down to the bottom base KN, it makes two equal lengths on either side. 13 - 3 = 10
KH = 5
HN = 8
You can use the Pythagorean theorem to find the altitude (LH).
8² + (LH)² = (√89)²
64 + (LH)² = 89
(LH)² = 89 - 64
(LH)² = 25
LH = 5
Soh Cah Toa
Tan(LKN) = 5/5
inverse trig function
∠LKN = 45°
</span></span></span>
Answer:
∠ 2 = 86°
Step-by-step explanation:
Vertical angles are congruent, thus equating gives
20x - 14 = 17x + 1 ( subtract 17x from both sides )
3x - 14 = 1 ( add 14 to both sides )
3x = 15 ( divide both sides by 3 )
x = 5
Thus
∠ 2 = 20x - 14 = 20(5) - 14 = 100 - 14 = 86°
This is an irrational number because 3 is not a perfect square.
sqrt4 = 2 and sqrt 1 = 1
So sqrt3 is Greater than 1 and less than 2.
sqrt3 is approx. 1.7
