Can someone pleaseee help me with this.

7.1.35-T Question Help You are the operations manager for an airline and you are considering a higher fare level for passengers

shusha [124]

Answer:

You must survey 784 air passengers.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Assume that nothing is known about the percentage of passengers who prefer aisle seats.

This means that $\pi = 0.5$ , which is when the largest sample size will be needed.

Within 3.5 percentage points of the true population percentage.

We have to find n for which M = 0.035. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.035 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.035\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.035}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.035})^2$

$n = 784$

You must survey 784 air passengers.

6 0

3 years ago

Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co

ycow [4]

Answer:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

$y= x^2 -6x +14$

We can complete the square like this:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

4 0

4 years ago

A university knows from historical data that 25% of students in an introductory statistics class withdraw before completing the

Vikki [24]

Answer:

13.4%

Step-by-step explanation:

Use binomial probability:

P = nCr p^r q^(n-r)

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1-p).

Here, n = 16, r = 2, p = 0.25, and q = 0.75.

P = ₁₆C₂ (0.25)² (0.75)¹⁶⁻²

P = 120 (0.25)² (0.75)¹⁴

P = 0.134

There is a 13.4% probability that exactly 2 students will withdraw.

8 0

3 years ago

Determine 2nd term and rth term of a.p.whose 6 th term is 12 and 8 th term is 22

Vanyuwa [196]

Answer:

see explanation

Step-by-step explanation:

The n th term of an arithmetic progression is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given $a_{6}$ = 12 and $a_{8}$ = 22, then

a₁ + 5d = 12 → (1)

a₁ + 7d = 22 → (2)

Subtract (1) from (2) term by term to eliminate a₁

2d = 10 ( divide both sides by 2 )

d = 5

Substitute d = 5 into (1) to find a₁

a₁ + 5(5) = 12

a₁ + 25 = 12 ( subtract 25 from both sides )

a₁ = - 13

Thus

$a_{2}$ = - 13 + 5 = - 8

$a_{n}$ = - 13 + 5(n - 1) = - 13 + 5n - 5 = 5n - 18 ← n th term

8 0

3 years ago

Square root 4x divided by 2x+1= 3 solve

Citrus2011 [14]

Answer:

See attached photo

Step-by-step explanation:

3 0

3 years ago