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2 years ago

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If the weight of a package is 3/10 the result is 7.2 pounds. find the weight of the package

1 answer:

Aneli [31]2 years ago

7 0

Answer:

Weight = 3/10

Result = 7.2

Let the weight of package be x

3x/10 = 7.2

x = 72/3

x = 24 pounds

Hope this helps!

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1.) $x=8\sqrt{3};y=16$

2.) $x=1;y=\frac{\sqrt{3}}{2}$

3.) $x=28 ; y=14\sqrt{3}$

4.) $x=24 ; y=12\sqrt{3}$

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Step-by-step explanation:

Use the 30°-60°-90° formulas:

a. $longer$ $leg=\sqrt{3}*shorter$ $leg$

b. $hypotenuse=2*shorter$ $leg$

1.) Insert values for a:

$x=\sqrt{3}*8$

Simplify:

$x=8\sqrt{3}$

Insert values for b:

$y=2*8$

Simplify:

$y=16$

2.) Insert values for a:

$y=\sqrt{3}*\frac{1}{2}$

Simplify:

$y=\frac{\sqrt{3}}{2}$

Insert values for b:

$x=2*\frac{1}{2}$

Simplify:

$x=1$

3.) Insert values for a:

$y=\sqrt{3}*14$

Simplify:

$y=14\sqrt{3}$

Insert values for b:

$x=2*14$

Simplify:

$x=28$

4.)Insert values for a:

$y=\sqrt{3}*12$

Simplify:

$y=12\sqrt{3}$

Insert values for b:

$x=2*12$

Simplify:

$x=24$

5.) Insert values for a:

$12=\sqrt{3}*x$

Divide both sides by $\sqrt{3}$ and rationalize:

$\frac{12}{\sqrt{3}}=\frac{\sqrt{3}*x}{\sqrt{3}}\\\\\frac{12}{\sqrt{3}}=x\\\\\frac{\sqrt{3}}{\sqrt{3}}*\frac{12}{\sqrt{3}}\\\\\frac{12\sqrt{3}}{\sqrt{9}}\\\\\frac{12\sqrt{3}}{3}\\\\4\sqrt{3}=x$

Flip:

$x=4\sqrt{3}$

Insert values for b:

$y=2*4\sqrt{3}$

Simplify:

$y=8\sqrt{3}$

6.) Insert values for a:

$8=\sqrt{3}*x$

Divide both sides by $\sqrt{3}$ and rationalize:

$\frac{8}{\sqrt{3}}=\frac{\sqrt{3}*x}{\sqrt{3}}\\\\\frac{8}{\sqrt{3}}=x\\\\\frac{\sqrt{3}}{\sqrt{3}}*\frac{8}{\sqrt{3}}\\\\\frac{8\sqrt{3}}{\sqrt{9}}\\\\\frac{8\sqrt{3}}{3}=x$

Flip:

$x=\frac{8\sqrt{3}}{3}$

Insert values for b:

$y=2*\frac{8\sqrt{3}}{3}$

Simplify:

$y=\frac{16\sqrt{3}}{3}$

Finito.

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2 years ago