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3 years ago

9

Evib graphs the parabola y = x^2 + 4x + 7 and finds that it has no x-intercepts. Explain how you can verify Evin's result algebr

aically by solving for the zeroes of the function.

1 answer:

Andrew [12]3 years ago

4 0

I found the key to the worksheet: https://tinyurl.com/y8a3amom.
copy and paste.

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3 years ago

How do I solve quadratic equations for example,h(t) = – 0.07t2 + 0.007t + 5

g100num [7]

Answer:

x ≈ -8.402, 8.502

Step-by-step explanation:

The usual methods of solving quadratic equations apply to this one. Any of them can be used: graphing, factoring, completing the square, quadratic formula.

<h3>Solution</h3>

Often, when the coefficients are non-integers and have no obvious relationship to each other, the most convenient method of solution is the quadratic formula. It tells you the solution to ax²+bx+c=0 is ...

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Your equation has the coefficients, a = -0.07, b = 0.007, c = 5, so the solutions are ...

$x=\dfrac{-0.007\pm\sqrt{0.007^2-4(-0.07)(5)}}{2(-0.07)}=\dfrac{-0.007\pm\sqrt{1.400049}}{-0.14}\\\\x=0.05\pm\sqrt{\dfrac{200007}{2800}}=0.05\pm\sqrt{71.4310\overline{714285}}\\\\\boxed{x\approx\{-8.40169,\,8.50169\}}$

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