4 years ago

Algebra 2 help? :))))

1 answer:

5 0

Just look at the photos

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satela [25.4K]

Answer:

$3a^4$

Step-by-step explanation:

Given expression is $27a^{12}$ .

Now we need to find the cube root of given expression $27a^{12}$ .

$\sqrt[3]{27a^{12}}$

$=\sqrt[3]{3*3*3a^{4*3}}$

$=\sqrt[3]{3^3\left(a^4\right)^3}$

$=\sqrt[3]{\left(3a^4\right)^3}$

Since cube root and cube are opposite operations of each other. So they will cancel each other.

$=3a^4$

Hence correct choice is the last choice $3a^4$ .

8 0

3 years ago

Natasha2012 [34]

Answer:

the absoulute value of -7 is 7

8 0

4 years ago

stepan [7]

i think that it is 2.2\4=0.55

7 0

3 years ago

algol13

Part one of your questions would be 1/20
Part two would be 1/20
Part three. Yes they are equal
Part four. None of them sense there equal

6 0

3 years ago

Maslowich

Answer: the heck is that?

Step-by-step explanation:

6 0

3 years ago