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kipiarov [429]
3 years ago
10

Suppose that y varies directly with x, and y=3 when x=8

Mathematics
1 answer:
spayn [35]3 years ago
4 0

we are given

y varies directly with x

so, we can write equation as

y=kx

where

k is a constant

now, we need to find k

we are given

y=3 when x=8

so, we can plug it and find k

3=k*8

k=\frac{3}{8}

now, we can plug it back

y=\frac{3}{8}x

(A)

we have got equation as

y=\frac{3}{8}x

for finding inverse , we can switch x and y

x=\frac{3}{8}y

now, we can solve for y

8*x=8*\frac{3}{8}y

8*x=3y

f^{-1}(x)=\frac{8x}{3}............Answer

(B)

we have

y=\frac{3}{8}x

we can plug x=4 and find y

y=\frac{3}{8}*4

y=\frac{3}{2}................Answer

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The second term of the expansion is -4a^3b.

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