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guapka [62]
3 years ago
14

What’s the correct answer I need a correct answer ASAP!!!!!

Mathematics
1 answer:
Illusion [34]3 years ago
5 0

Answer:

the first answer

3 1/3 that's the correct answer

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Analyze a graph In Exercise,analyze and sketch the graph of the function.Label any relative extrema, points of inflation,and asy
FinnZ [79.3K]

Answer:

Step-by-step explanation:

Given is a function of x

f(x) = xe^{-x}

When y=0 we get x=0 and infinity

Hence x intercept is 0 and one asymptote is x axis.

When x=0 , y =0

f'(x) = e^{-x}(-x+1)

f''(x) = e^{-x}(x-1-1)

Maxima at x=1, and point of inflection is at x=2

Increasing upto x=1 and then decreases

Graph is enclosed

6 0
3 years ago
Please solve with explanation 9 points
Levart [38]

Step-by-step explanation:

try the option shown in the attachment, note, all the answers are marked with red colour.

8 0
2 years ago
a copy shot prints 5,493 pages they use the pages to make 68 same size booklets about how many pages are in each booklet
Aliun [14]

Answer:

80 pages

Step-by-step explanation:

Given:

Number of pages printed = 5493

Number of booklets made = 68

Let each booklet use 'x' pages.

So, pages used by 68 booklets is given by unitary method and is equal to:

=68\times x\\=68x

Now, total number of pages are 5493.

Therefore, the pages used by the 68 booklets should be less than or equal to the total number of pages available. So,

68x=5493\\\textrm{Dividing both sides by 68,we get:}\\x=\frac{5493}{68}=80.8\approx 80(\textrm{As number of pages can't be in decimal})

Therefore, the number of pages in each booklet is 80.

3 0
3 years ago
Movie Ticket Sales : 6x + 9y = 1,500 Suppose on this day all tickets were on sale for the child price of $6. How many tickets we
dedylja [7]
The answer to the question

6 0
3 years ago
Read 2 more answers
Solve the inequality: (x+3)(x−4)<−12
melamori03 [73]

Answer:

0<x<1

Step-by-step explanation:

(x+3)(x−4)<−12

FOIL

x^2 -4x+3x -12 <-12

x^2 -x -12 <-12

Add 12 to each side

x^2 -x -12+12 <-12+12

x^2 -x <0

Factor out an x

x(x-1) <0

Using the zero product property

x(x-1) =0

x=0  x-1=0

x=0  x=1

Check the ranges

x<0

x(x-1) <0        

- * - >0

False

0<x<1

x(x-1) <0        

+ * - <0

True

x>1

x(x-1) <0        

+ * + >0

False

3 0
3 years ago
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