The sum of angles of a triangle is 180°, so m∠K = 180° -45° -30° = 105°.
The Law of Sines tells you
... FL/sin(∠K) = FK/sin(∠L)
Solving for FL, we get
... FL = FK·sin(∠K)/sin(∠L)
... FL = a·sin(105°)/sin(30°) = a·sin(105°)/(1/2)
... FL = 2a·sin(105°) ≈ 1.93185a
Answer and explanation:
They are not equivalent because if we simplify the second expression, the result isn't the same:
7(y×b)+3b
= 7(yb)+3b
=7yb + 3b
Therefore 7yb+3b≠7y+7b+3y
And even though you meant
7(y+b)+3b
=7y+7b+3b
=7y+10b
7y+10b≠10y+7b
3x=5x+18
3x-3x=5x-3x+18
0=2x+18
0-18=2x+18-18
-18=2x
-18÷2=2x÷2
-9=x
Hope this helps!
Vote me brainliest!
Let x represent the first number, y represent the second, and z represent the third.
x + y + z = 92
z = 3x
x = y - 7
Solve x = y - 7 for y.
x = y - 7
x + 7 = y
Fill in y and z so that we only have to worry about x for now.
x + y + z = 92
x + (x + 7) + (3x) = 92
x + x + 7 + 3x = 92
5x + 7 = 92
5x = 92 - 7
5x = 85
x = 85/5
x = 17
Solve for y.
y = x + 7
y = (17) + 7
y = 24
Solve for z.
z = 3x
z = 3(17)
z = 51
So x = 17, y = 24, and z = 51.
