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Blababa [14]
4 years ago
14

What is 2 5/8 estimated to the nearest whole number

Mathematics
1 answer:
mamaluj [8]4 years ago
6 0

Answer:

the answer to your question is 3

Step-by-step explanation:

2 and 5/8 is 2.625 rounding gives you 3

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Which expression is equivalent to<br> (4^5/4.4^1/4/4^1/2
marshall27 [118]

Answer:

Which expression is equivalent to ((4^((5)/(4)).4^((1)/(4)))/(4^((1)/(2))))^((1)/(2))?

3 0
4 years ago
A circumference of 320 cm what is the radius
alina1380 [7]
Radius = 50.93

Diameter = 101.86

Area = 8148.87
7 0
2 years ago
One bridge is 4260ft and the other is 760ft. What is the length?
pentagon [3]

The total length of the two bridges is 5020 ft.

In order to find the combined length of these two bridges, simply add the two numbers together.

4260 + 760 = 5020.

8 0
4 years ago
A store has been selling 100 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere
Sav [38]

Answer:

<em>The rebate should be $220</em>

Step-by-step explanation:

<u>Demand Curve</u>

It's the relationship between price (P) and quantity (Q) demanded a certain product or service.

(a) We need to find the function that relates both magnitudes assuming a linear equation. The equation of a line can be found with the point-point formula:

\displaystyle Q-Q_1=\frac{Q_2-Q_1}{P_2-P_1}(P-P_1)

Two sets of data are given: 100 Blu-ray disc players are sold a week at $600 each. The ordered pair for this condition is (P,Q)=(600,100).

The other point comes from the market survey: The number of units sold will increase by 80 (100+80=180) when the price goes down $40 (600-40=560). The new point is (P,Q)=(560,180)

We set up the equation of the demand

\displaystyle Q-100=\frac{180-100}{560-600}(P-560)

Rearranging

-40Q+4000=80P-44800

Or

80P+40Q=48800

Simplifying

2P+Q=1120

(b) The revenue function is Q times the price

R=Q.P

Solving the equation of the demand for P

\displaystyle P=\frac{1120-Q}{2}

Thus, the revenue is

\displaystyle R=Q\cdot \frac{1120-Q}{2}

\displaystyle R=\frac{1120Q-Q^2}{2}

(c) To find the optimum value of the revenue, we take the derivative of R and equate to 0

\displaystyle R'=\frac{1120-2Q}{2}=560-Q=0

Solving

Q=560 units a week

For which the revenue is

\displaystyle R=\frac{1120(560)-560^2}{2}

R=\$156,800

And the price is

\displaystyle P=\frac{1120-560}{2}=280

P=\$280

The rebate should be $600-$280=$220

4 0
3 years ago
32% of what number is 56
attashe74 [19]
Let 32% of x = 56

32%*x = 56
32/100 *x = 56
x = 56*100/32
x = 5600/32 = 175

hence, 32% of 175 is 56.
5 0
3 years ago
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