So we have the following system of equations:
![\begin{gathered} 4x+3y=5 \\ x=4y+6 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%204x%2B3y%3D5%20%5C%5C%20x%3D4y%2B6%20%5Cend%7Bgathered%7D)
We need to solve it by substitution. This means that we have to take the expression for x given by the second equation and replace x with it in the first equation:
![\begin{gathered} 4x+3y=5 \\ 4\cdot(4y+6)+3y=5 \\ 16y+24+3y=5 \\ 16y+3y=5-24 \\ 19y=-19 \\ y=-\frac{19}{19}=-1 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%204x%2B3y%3D5%20%5C%5C%204%5Ccdot%284y%2B6%29%2B3y%3D5%20%5C%5C%2016y%2B24%2B3y%3D5%20%5C%5C%2016y%2B3y%3D5-24%20%5C%5C%2019y%3D-19%20%5C%5C%20y%3D-%5Cfrac%7B19%7D%7B19%7D%3D-1%20%5Cend%7Bgathered%7D)
So y=-1. If we use this value in the second equation:
![\begin{gathered} x=4y+6 \\ x=4\cdot(-1)+6 \\ x=-4+6 \\ x=2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D4y%2B6%20%5C%5C%20x%3D4%5Ccdot%28-1%29%2B6%20%5C%5C%20x%3D-4%2B6%20%5C%5C%20x%3D2%20%5Cend%7Bgathered%7D)
So we have x=2 and y=-1 which means that there's one solution. Then the correct answer is A and the solution is (2,-1).
Since the matrices have different dimensions, it is not possible to calculate the expression...
- <em>T</em><em>h</em><em>u</em><em>s</em><em>,</em><em> </em><em>O</em><em>p</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>C</em><em> </em><em>i</em><em>s</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em>!</em><em>!</em><em>~</em>
An equilateral is your answer my boi
Answer:
x = 10
Step-by-step explanation:
Since M is at the midpoint of TL , then
TM = ML , substitute values
2x + 8 = 3x - 2 ( subtract 2x from both sides )
8 = x - 2 ( add 2 to both sides )
10 = x , that is x = 10
Answer:
13 ounces
Step-by-step explanation:
291/21.5=13.5348837209