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mamaluj [8]
3 years ago
10

Which expression is equivalent to (4^5/4.4^1/4/4^1/2

Mathematics
1 answer:
marshall27 [118]3 years ago
3 0

Answer:

Which expression is equivalent to ((4^((5)/(4)).4^((1)/(4)))/(4^((1)/(2))))^((1)/(2))?

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5.3.24 A is a 3times3 matrix with two eigenvalues. Each eigenspace is​ one-dimensional. Is A​ diagonalizable? Why? Select the co
abruzzese [7]

Answer:

C. No. The sum of the dimensions of the eigenspaces equals nothing and the matrix has 3 columns. The sum of the dimensions of the eigenspace and the number of columns must be equal.

Step-by-step explanation:

Here the sum of dimensions of eigenspace is not equal to the number of columns, so therefore A is not diagonalizable.

5 0
3 years ago
Complete the sentence about pattern G and pattern H. Use the table to help.
Xelga [282]
The answer is ‘4 times’
5 0
2 years ago
Simplify fully <br>2/(5x)+2x/3<br>​
lara31 [8.8K]

Answer:

16x / 15

Step-by-step explanation:

2/5x + 2x/3

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7 0
3 years ago
The first two numbers in a sequence h are h(1) = 2 and h(2) = 6.
Ghella [55]

Answer:

Step-by-step explanation:

Given the first two numbers of a sequence as 2, 6...

If it is an arithmetic difference, the common difference will be d = 6-2 = 4

Formula for calculating nth term of an ARITHMETIC sequence Tn = a+(n-1)d

a is the first term = 2

d is the common difference = 4

n is the number if terms

Substituting the given values in the formula.

Nth term Tn = 2+(n-1)4

Tn = 2+4n-4

Tn = 4n-4+2

Tn = 4n-2

2) If the sequence us a geometric sequence

Nth term of the sequence Tn = ar^(n-1)

r is the common ratio

r is gotten by the ratio of the terms I.e

r = T2/T1

r = 6/2

r = 3

Since a = 2

Tn = 2(3)^(n-1)

Hence the nth term of the geometric sequence is Tn = 2(3)^(n-1)

3 0
3 years ago
Somebody please help I need to know how to do this for a big test.
Valentin [98]
No because 3 can go into 63 evenly and the denominator would be left the same.
4 0
3 years ago
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