A quadratic function is given by y = ax^2 + bx + c
c(2) = a(2)^2 + 2b + c = 45
4a + 2b + c = 45 . . . (1)
c(4) = a(4)^2 + 4b + c = 143
16a + 4b + c = 143 . . . (2)
c(10) = a(10)^2 + 10b + c = 869
100a + 10b + c = 869 . . . (3)
Solving (1), (2) and (3) gives a = 9, b = -5, c = 19
Therefore, c(x) = 9x^2 - 5x + 19
c(7) = 9(7)^2 - 5(7) + 19 = 9(49) - 35 + 19 = 441 - 16 = 425
Therefore, it costs $425 to produce 7 calculators.
Here's our equation.

Let's reorder this so t² comes before t.

We want to find out when the ball hits the ground. Essentially, <em>what is t when h=0?</em>
Let's plug in 0 for h and solve.

From here we can use a number of methods to solve.
Methods such as splitting the middle, quadratic formula, etc. are not necessary for this equation, however. The best method here is just plain factoring.
-16t² and 176t are both divisible by 16t.

Now we want t to equal zero. If either of those factors were zero, then the whole thing would be zero when we multiply by it. The first option is obvious. If t were 0, 16t would be 0. That's when the ball is first kicked off the ground. The other, 11-t, works out to be
t = 11.
Answer:
6
Step-by-step explanation:
Answer:
GE=10
FJ=5
Step-by-step explanation:
We know that in a traingle

a=HE=6
b=FE=8
Once we enter it into the equation, we find that we get
36+64=100
The square root of 100=10
GE=HF so HE=10.
Half of HE(10) is FJ(5)
Hope this help :)
5x + 3 is a linear equation in one variable