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Lelu [443]
4 years ago
7

Suppose a current-carrying wire has a cross-sectional area that gradually becomes smaller along the wire, so that the wire has t

he shape of a very long,truncated cone. How does the drift speed vary along the wire?
Physics
1 answer:
SIZIF [17.4K]4 years ago
3 0

Answer:

It slows down as the cross-section becomes smaller is the correct answer to this question.

Explanation:

  • That current is the same in all parts of the wire under steady-state conditions.
  • Thus the velocity of drift is approximately equal to the cross‐sectional region.
  • vd = I /nAq .
  • As the cross-section gets smaller it accelerates.
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495m

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ANSWER

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3 years ago
Scientific advances have led to decreased energy efficiency and waste reduction. please select the best answer from the choices
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It is false that scientific advances have led to decreased energy efficiency and waste reduction. 
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n200080 [17]

Answer:

(See explanation for further information)

Explanation:

a) The distances of each planet with respect to the Sun is:

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Mars - 141.600\times 10^{6}\,mi

Jupiter - 483.800\times 10^{6}\,mi

Saturn - 888.200\times 10^{6}\,mi

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b) The solutions are presented below:

A. The distance between Venus and Jupiter is:

\Delta s = 483.800\times 10^{6}\,mi-67.240\times 10^{6}\,mi

\Delta s = 416.560\times 10^{6}\,mi

B. The combined distance from the Sun is:

\Delta s = 57.909\times 10^{6}\,mi + 67.240\times 10^{6}\,mi +92.960\times 10^{6}\,mi

\Delta s = 218.109\times 10^{6}\,mi

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C. The new distance of Earth is 929.60 \times 10^{6}\,mi (929,600,000\,mi). Saturn would be the closest planet to Earth, whose distance:

Scientific notation:

\Delta s = 929.600\times 10^{6}\,mi-888.200\,\times 10^{6}\,mi

\Delta s = 41.4\times 10^{6}\,mi

Standard notation:

\Delta s = 929,600,000\,mi - 888,200,000\,mi

\Delta s = 41,400.000\,mi

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4 years ago
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